Find the slope and the x and y-intercept of the equation 2x-3y=12

HELP ASAP I REALLY NEED IT MY HEAD HURT BECAUSE OF THIS PLS WOULD GIVE 30pts If Jim spins the spinner 16 times, how many times w

Anvisha [2.4K]

Answer:

the answerr is 4

Step-by-step explanation:

please mark me the brainiest

8 0

2 years ago

What is the solution set for 4x+ 9 <17?

Natali5045456 [20]

Answer:

The awnser is d i think

7 0

2 years ago

Read 2 more answers

How to solve using Substitution or Elimination?<br> y=3x-1<br><br> y=2x+2

n200080 [17]

By elimination:

y = 3x - 1

y = 2x + 2

Subtract the second equation from the first

0 = x - 1

y = 2x + 2

Subtract the first equation from the second

0 = x - 1

y = x + 3

Subtract the first equation from the second again

0 = x - 1

y = 4

Subtract x from both sides of the first equation

- x = - 1

y = 4

Divide the first equation by (-1)

x = 1

y = 4

<h3>So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>

4 0

3 years ago

Find the smallest number such that the remainder is 3 when it is divided by 16,20 or 24.

schepotkina [342]

Answer: 123

Step-by-step explanation:

Foe us to solve this, we have to find the lowest common multiple of 16, 20 and 24 first and then add 3 to the LCM. This goes thus:

Multiples of 16 = 16, 32, 48, 64, 80, 96, 112, 128, 144, 160

Multiples of 20 = 20, 40, 60, 80, 10, 120, 140, 160

Multiples of 24 = 24, 48, 72, 96, 120

Therefore, the Lowe's common multiple is 120.

We then add the remainder of 3 and this will give:

= 120 + 3

= 123

4 0

3 years ago

Suppose a production facility purchases a particular component part in large lots from a supplier. The production manager wants

musickatia [10]

Answer:

We need a sample size of at least 1161.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error for the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$\pi = 0.22$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample should she take?

We need a sample size of at least n.

n is found when $M = 0.02$

So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.645\sqrt{\frac{0.22*0.78}{n}}$

$0.02\sqrt{n} = 1.645\sqrt{0.22*0.78}$

$\sqrt{n} = \frac{1.645\sqrt{0.22*0.78}}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.22*0.78}}{0.02})^{2}$

$n = 1160.88$

Rounding up

We need a sample size of at least 1161.

7 0

3 years ago