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3 years ago

Which describes the

Mathematics

2 answers:

Mumz [18]3 years ago

5 0

Zero/x doesn’t change

gtnhenbr [62]3 years ago

5 0

Answer:

zero

Step-by-step explanation:

Horizontal lines have a slope of 0

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HELP PLEASE WILL GIVE BRAINLIEST

abruzzese [7]

Answer:
$1.21

Explanation:
What we know:
- $5.88=3 pounds of apples
- price went up by $0.75 per pound

First, we divide $5.88 by 3 to find out how much one pound of apples cost.

5.88/3
=1.96

Therefore, the new price of apples per pound is $1.96.

Because the old price of apples per pound was $0.75 cheaper, we subtract 0.75 from 1.96.

1.96-0.75
=1.21

Therefore, the old price of apples per pound was $1.21.

I hope this helps! Please comment if you have any questions.

7 0

3 years ago

Read 2 more answers

Turn -3/11 into a decimal

lutik1710 [3]

-0.272727272727272727272727272727

4 0

3 years ago

Read 2 more answers

Find k if 3k, k-2, and k + 7 are consecutive terms of an arithmetic sequence.

ahrayia [7]

This is 1:25 (C)

Explanation:

6 0

3 years ago

If 3/4 of a stick of butter will make 3 dozen cookies how many sticks of butter will make be needed for 1 dozen

Lynna [10]

Answer:

$\frac{1}{4}$ stick of butter

Step-by-step explanation:

$\frac{3}{4}$ ÷ $3$ = $\frac{1}{4}$

6 0

3 years ago

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$

Volume of the box at x= 1.59:

$V = \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\$

Volume of the box at x= 0.53:

$V = \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3$

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

7 0

3 years ago