Multiply & Simplify 1/4×6<br>please solve

Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap

pantera1 [17]

Answer:

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e $\dfrac{dV}{dt}= 20 \ ft^3/min$

we know that radius r is always twice the diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

$V = \dfrac{\pi r^2 h}{3}$

$V = \dfrac{\pi (h/2)^2 h}{3}$

$V = \dfrac{1}{12} \pi h^3$

$V = \dfrac{ \pi h^3}{12}$

Taking the differentiation of volume V with respect to time t; we have:

$\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}$

$\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}$

we know that:

$\dfrac{dV}{dt}= 20 \ ft^3/min$

So;we have:

$20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}$

$20= 56.25 \pi \times \dfrac{dh}{dt}$

$\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

8 0

3 years ago

Find the equation of the exponential function represented by the table below:

aivan3 [116]

Answer:

I believe its y=5(4)^x

Step-by-step explanation:

The equation is supposed to look like y=ab^x

a is basically where it all starts, so where the y meets the 0

- so the 5 in the y's place meets the 0

b is what you're multiplying by on the y's side, which is by 4 every time

and the x is the exponent and since there is no exponent you leave it as x

4 0

3 years ago

Which represents the reference angle for 3pi/4?

inn [45]

Answer:

(c) Pi/4

Step-by-step explanation:

3pi/4 = (3 x 180) / 4 = 135 degrees

135 degrees is equivalent to (180 degrees - 135 degrees) 45 degrees

45 degrees = Pi/4

Therefore, the reference angle of 3pi/4 is Pi/4

Thus, the correct option is (c) Pi/4

8 0

3 years ago

A new neighborhood activity complex is being built in erie. The perimeter of the rectangular playing field is 256 yards. The len

maw [93]

Answer:

The length of the rectangular playing field is 84 yards and the width is 44 yards

Step-by-step explanation:

Let

x ------> the length of the rectangular playing field

y -----> the width of the rectangular playing field

we know that

The perimeter of the rectangular playing field is equal to

$P=2(x+y)$

$P=256\ yd$

so

$256=2(x+y)$ ------> equation A

we have that

$x=2y-4$ -----> equation B

Solve the system by substitution

Substitute equation B in equation A and solve for y

$256=2(2y-4+y)$

$128=3y-4$

$3y=128+4$

$3y=132$

$y=44$

Find the value of x

$x=2(44)-4=84$

therefore

The length of the rectangular playing field is 84 yards and the width is 44 yards

4 0

3 years ago

For questions 8-10 in the diagram below, AB is parallel to CD. Use the diagram to find the unknown angles

telo118 [61]

Answer:

x=78°

y=78°

z=102°

Step-by-step explanation:

x=78°

y=78°

z=180-78=102°

8 0

3 years ago

Multiply & Simplify 1/4×6please solve ​

Multiply & Simplify 1/4×6please solve