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prohojiy [21]
3 years ago
13

16 2/5 - 9 2/3 = show work

Mathematics
1 answer:
fgiga [73]3 years ago
3 0

Answer:

Conversion a mixed number 16 3

8

to a improper fraction: 16 3/8 = 16 3

8

= 16 · 8 + 3

8

= 128 + 3

8

= 131

8

To find new numerator:

a) Multiply the whole number 16 by the denominator 8. Whole number 16 equally 16 * 8

8

= 128

8

b) Add the answer from previous step 128 to the numerator 3. New numerator is 128 + 3 = 131

c) Write previous answer (new numerator 131) over the denominator 8.

Sixteen and three eighths is one hundred thirty-one eighths

Conversion a mixed number 9 5

8

to a improper fraction: 9 5/8 = 9 5

8

= 9 · 8 + 5

8

= 72 + 5

8

= 77

8

To find new numerator:

a) Multiply the whole number 9 by the denominator 8. Whole number 9 equally 9 * 8

8

= 72

8

b) Add the answer from previous step 72 to the numerator 5. New numerator is 72 + 5 = 77

c) Write previous answer (new numerator 77) over the denominator 8.

Nine and five eighths is seventy-seven eighths

Subtract: 131

8

- 77

8

= 131 - 77

8

= 54

8

= 2 · 27

2 · 4

= 27

4

The common denominator you can calculate as the least common multiple of the both denominators - LCM(8, 8) = 8. Cancelling by a common factor of 2 gives 27

4

.

In words - one hundred thirty-one eighths minus seventy-seven eighths = twenty-seven quarters.

Step-by-step explanation:

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3 years ago
let x1,x2, and x3 be linearly independent vectors in R^(n) and let y1=x2+x1; y2=x3+x2; y3=x3+x1. are y1,y2,and y3 linearly indep
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Answer with Step-by-step explanation:

We are given that

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b_1y_1+b_2y_2+b_3y_3=0

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b_1+b_2=0

b_1=-b_2..(2)

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From equation (1) and (3)

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Adding equation (2) and (4)

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b_1=0

From equation (1) and (2)

b_3=0,b_2=0,b_3=0

Hence, y_1,y_2 and y_3 area linearly independent.

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