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Ivan
3 years ago
7

There are 72 eight grade students and 84 sixth grade students participating in the Fun Run competition. The students will be put

into groups among their own grade and into the largest possible equal groups with no students left over. How many students will be in each group? Group of answer choices
Mathematics
1 answer:
tatiyna3 years ago
3 0

Answer:

12 students

Step-by-step explanation:

Given that:

Eighth grade student = 72

Sixth grade student = 84

To group the students into the largest possible equal group with no student left, obtain the greatest common factor of the number of sixth grade and eighth grade student

Factors of 72:

72 : 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36

84 : 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 81

The greatest factor common in both numbers is 12.

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Ill give brainliest
Rzqust [24]

Answer:

<h2>c. (0, 2)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}m+4n=8&(1)\\m=n-2&(2)\end{array}\right\\\\\text{substitute (2) to (1):}\\\\n-2+4n=8\qquad\text{add 2 to both sides}\\5n=10\qquad\text{divide both sides by 5}\\n=2\\\\\text{put the value of}\ n\ \text{to (2):}\\\\m=2-2\\m=0

4 0
3 years ago
How do you find degree measures? How would you solve this question?
MrRa [10]
A. a=145 b=35 c=145 d=145 e=35 f=145 g=35

b. These are the pairs of vertical angles: a & c, b & 35, d & f, e & g.

Hope this was helpful.
8 0
3 years ago
-<br> A rectangular prism has how many flat surfaces?
Scrat [10]

Answer:

it has 6 faces

Step-by-step explanation:

8 0
3 years ago
If avogadro's number of pennies is divided equally among the 231 million men, women, and children in the united states, how many
Anon25 [30]
<span>2.607 x 10^13 dollars per person. Avogadro's number is approximately 6.0221409x10^23. So divide by the 231 million people. Giving (6.0221409 x 10^23) / (231 x 10^6) = 0.02607 x 10^17 = 2.607 x 10^15 pennies But we want dollars, so divide by 100 2.607 x 10^15 / 100 = 2.607 x 10^13 dollars</span>
4 0
3 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
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