Answer:
The answer to your question is below
Step-by-step explanation:
5) 2x² -7x + 34
x + 5 2x³ + 3x² - x + 1
-2x³ -10x²
0 - 7x² - x
+7x² +35x
0 +34x + 1
-34x - 170
0 - 160
Quotient = 2x² - 7x + 34
Remainder = -160
6) 2x² - 3x + 1
3x + 1 6x³ - 7x² + 0x + 2
-6x³ -2x²
0 -9x² + 0x
+9x² +3x
0 +3x + 2
- 3x - 1
0 + 1
Quotient = 2x² - 3x + 1
Remainder = 1
Answer:
Two.
Step-by-step explanation:
Simultaneous equation is a Finite sets of equations whose common solutions are sought.
Two solutions in the equation above is sought.
Solution :
a).
Given : Number of times, n = 25
Sigma, σ = 0.200 kg
Weight, μ = 13 kg
Therefore the hypothesis should be tested are :


b). When the value of 
Test statics :



= 45.5
P-value = 2 x P(Z > 45.5)
= 2 x 1 -P (Z < 45.5) = 0
Reject the null hypothesis if P value < α = 0.01 level of significance.
So reject the null hypothesis.
Therefore, we conclude that the true mean measured weight differs from 13 kg.
They are equivalent ! both are 14