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gladu [14]
4 years ago
7

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

w that the statement is not always true. Such an example is called a counterexample to the statement. If the statement is true, give a justification. If v1,…,v4 are in R4 and {v1,v2,v3} is linearly dependent then {v1,v2,v3,v4} is also linearly dependent.
Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.

(A) True. Because v3 = 2v1 + v2, v4 must be the zero vector. Thus, the set of vectors is linearly dependent.
(B) True. The vector v3 is a linear combination of v1 and v2, so at least one of the vectors in the set is a linear combination of the others and set is linearly dependent.
(C) True. If c1 =2, c2 = 1, c3 = 1, and c4 = 0, then c1v1 + ........... + c4v4 =0. The set of vectors is linearly dependent.
(D) False. If v1 = __, v2 =___, v3 =___, and v4 = [1 2 1 2], then v3 = 2v1 + v2 and {v1, v2, v3, v4} is linearly independent.
Mathematics
1 answer:
LUCKY_DIMON [66]4 years ago
8 0

Answer with Step-by-step explanation:

We are given that v_1,v_2,..,v_4 are in R^4 and v_1,v_2,v_3 is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is  a linear combination of other given vectors.

Or If we have vectors x_1,x_2,....x_n

Then their linear combination

a_1x_1+a_2x_2+.....+a_nx_n=0

There exist at least one scalar which is not zero.

If v_1,v_2,v_3 are dependent vectors then

a_1v_1+a_2v_2+a_3v_3=0 for scalars a_1,a_2,a_3

Then , by definition of dependent  vectors

There exist a vector which is not equal to zero

If vector v_3 is a linear combination of v_1\;and \;v_2, So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{v_1,v_2,v_3,v_4} is linearly dependent.

Option B is true.

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Answer:

1. 4x(x^2+5x+4)

2. 2x^2(6x^2+13x-8)

3. 2(5x^2+24x-5)

Step-by-step explanation:

1.

The common factor between all the monomials is 4x, so we divide each by 4x.

2.

The common factor between all the monomials is 2x^2, so we divide each by 2x^2.

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The common factor between all the monomials is 2, so we divide each by 2.

6 0
3 years ago
the data set represents the total number of tickets each person purchased for a play. 0, 0, 1, 1, 1, 2, 2, 2, 4, 4 what is the m
Helen [10]

The median of the data 0, 0, 1, 1, 1, 2, 2, 2, 4, 4 is 1.5

There are three measures of central dispersion:

  • Mean: This is the average of the given data in the distribution.

  • Median: It is the middle value of the set when the set is either arranged in ascending or descending order.

  • Mode: This is the value that has the largest occurrence in the distribution.

Given:

0, 0, 1, 1, 1, 2, 2, 2, 4, 4

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So, we have two middle values: 1 and 2

Median = (1 + 2) / 2

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Therefore, the median of the data 0, 0, 1, 1, 1, 2, 2, 2, 4, 4 is 1.5

Learn more about median:

brainly.com/question/8892632

7 0
3 years ago
What is the reciprocal for 2 2/5​
wariber [46]

Answer:

5/12

Step-by-step explanation:

2 2/5 = 12/5 so its reciprocal is 5/12

Reciprocals are fractions that are basically "flipped". You flip the denominator to the numerator and vice versa.

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Answer: its 9 units ok yea


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3 years ago
Solve for e. 9e^2f=49<br> e=±√7f/3<br> e=±7√f/3<br> e=±7√f/3f<br> e=±√7f/3f
Vesnalui [34]
Divide by the coefficient of e^2, then take the square root.
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  e = ±7/(3√f) = ±(7√f)/(3f)

The 3rd selection is appropriate:
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When written in plain text (not typeset), any denominator containing arithmetic must be enclosed in parentheses. When the expression is typeset, the surd and the division bar do the grouping for you.
  e=\pm \dfrac{7\sqrt{f}}{3f}
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