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gladu [14]
3 years ago
7

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

w that the statement is not always true. Such an example is called a counterexample to the statement. If the statement is true, give a justification. If v1,…,v4 are in R4 and {v1,v2,v3} is linearly dependent then {v1,v2,v3,v4} is also linearly dependent.
Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.

(A) True. Because v3 = 2v1 + v2, v4 must be the zero vector. Thus, the set of vectors is linearly dependent.
(B) True. The vector v3 is a linear combination of v1 and v2, so at least one of the vectors in the set is a linear combination of the others and set is linearly dependent.
(C) True. If c1 =2, c2 = 1, c3 = 1, and c4 = 0, then c1v1 + ........... + c4v4 =0. The set of vectors is linearly dependent.
(D) False. If v1 = __, v2 =___, v3 =___, and v4 = [1 2 1 2], then v3 = 2v1 + v2 and {v1, v2, v3, v4} is linearly independent.
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer with Step-by-step explanation:

We are given that v_1,v_2,..,v_4 are in R^4 and v_1,v_2,v_3 is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is  a linear combination of other given vectors.

Or If we have vectors x_1,x_2,....x_n

Then their linear combination

a_1x_1+a_2x_2+.....+a_nx_n=0

There exist at least one scalar which is not zero.

If v_1,v_2,v_3 are dependent vectors then

a_1v_1+a_2v_2+a_3v_3=0 for scalars a_1,a_2,a_3

Then , by definition of dependent  vectors

There exist a vector which is not equal to zero

If vector v_3 is a linear combination of v_1\;and \;v_2, So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{v_1,v_2,v_3,v_4} is linearly dependent.

Option B is true.

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Based on the tree diagram below, what is the probability that a student doesn't have lice, given that the student tested negativ
oee [108]

Answer:

Option D (APEX)

Step-by-step explanation:

L= Student has lice

NL= Student has no lice

PT=Test Shows positive

NT=Test Shows negative

P(\frac{NT}{NL}) =0.7708 (Probability that a student has no lice and the test shows negative)

P(\frac{NT}{L}) = 0.0108 ( Probability that a student has lice and the test shows negative)

  1. P\frac{NT}{NL} = \frac{P\frac{NT}{NL} }{P\frac{NT}{NL} +P\frac{NT}{L} }
  2. \frac{0.7708}{0.7708+00108}
  3. \frac{0.7708}{0.7816}
  4. 0.98618219 (Simplify)

<u> Terms Of Percentages</u>

0.98618219 × 100

=98.6

Therefore your answer is 98.6% (Option D)

APEX

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prohojiy [21]

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Step-by-step explanation:

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Step-by-step explanation:

Since it gives you x, you need to plug in the number given for it into the equation:

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