Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
Answer:
1
Step-by-step explanation:
9-8=1
Hope that this is helpful.
Have a nice day.
Answer:
5. 
Step-by-step explanation:
==>>We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.
Initial: 10,000
After 1 year
10,000 + (.5*10000)
10,000 + 5000 = 15,000
--
After 2 years
15,000 + (.5*15000)
15,000 + 7500 = 22,500
--
Let's try our equation.
*Edit: I just seen that the question is related to the picture question
Answer:
z=-4/3
Step-by-step explanation:
8=-6z
z=-8/6
z=-4/3
