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3 years ago

12

Select the graph of the solution. click until the correct graph appears. 2x - 1 > 5

1 answer:

Usimov [2.4K]3 years ago

5 0

Answer:

Our answer would be x > 3

I have attached a picture of the graph below.

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How does understanding the history of credit make you think differently about credit card or other forms of debt? (Subject is pe

Gennadij [26K]

Answer:

It doesn't matter that much

Step-by-step explanation:

I know it from last year

8 0

3 years ago

Find the Slope of the line through each pair of points: (-4,11),(1,-9)

kogti [31]

Answer:

rise/run= -20/5= -4/1=-4 slope

or you sound use the slope formula (y2-y1)/(x2-x1)

(-9-11)/(1+4)

-20/5

-4

Step-by-step explanation:

6 0

3 years ago

One hundred items are simultaneously put on a life test. Suppose the lifetimes

romanna [79]

Answer:

a) $\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

b) $\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( $i-1$ )st and the $ith$ failures. Then, the $T_{i}$ are independent with $\mathrm{T}_{\mathrm{i}}$ being exponential with rate $\frac{(101-i)}{200} .$

Therefore,

a) $E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]$

$=\sum_{i=1}^{5} \frac{200}{101-i}$

$\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

$b)$

The variance is given by, $\mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]$

$\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

7 0

4 years ago

20 Points! <br><br> Solve for x

Marrrta [24]

Answer:

so all x's have to be added together.

8x+5x+10x+7x=30x

-2+3=1

1dividedby30=30

x=30

hope this helps

7 0

3 years ago

Read 2 more answers

What is the factored form of the polynomal? x2-12x+27

lianna [129]

Answer:

The answer is $(x-9) (x-3)$ .

Step-by-step explanation:

This is because when you multiply them together you get

$x^{2}$ , $-9x$ , $-3x$ , and $27$

When you add the like terms you get,

$x^{2} - 12x +27$

6 0

3 years ago