Answer:
9) 1/48
11) 1/24
13) 5/16
14) 1/8
Step-by-step explanation:
9) P(A and 5) = 1/8 × 1/6
11) P(J and LT 3) = 1/8 x 2/6
13) P (consonant and odd) = 5/8 x 1/2
14) P ('M' or 'T' and GT 3) = [(1/8+1/8) × 1/2] = 2/8 x 1/2
Answer:
Range=65
Step-by-step explanation:
The highest is 66 the lowest is 1 so 66-1=65
Answer:
Mean: ![\bar x = 40.61](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2040.61)
![Median =40.2](https://tex.z-dn.net/?f=Median%20%3D40.2)
![Mode = 43.4](https://tex.z-dn.net/?f=Mode%20%3D%2043.4)
Step-by-step explanation:
Given
See attachment for data
Solving (a): The mean
Mean is calculated as:
![\bar x = \frac{\sum x}{n}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B%5Csum%20x%7D%7Bn%7D)
From the attached:
![n = 14](https://tex.z-dn.net/?f=n%20%3D%2014)
So, the mean is:
![\bar x = \frac{43.4+43.4+43.4+43.1+43.2+40.2+40.2+40.1+40.3+39.44+39.17+38.03+38.19+36.45}{14}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B43.4%2B43.4%2B43.4%2B43.1%2B43.2%2B40.2%2B40.2%2B40.1%2B40.3%2B39.44%2B39.17%2B38.03%2B38.19%2B36.45%7D%7B14%7D)
![\bar x = \frac{568.58}{14}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B568.58%7D%7B14%7D)
![\bar x = 40.61](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2040.61)
Solving (b): The median
; this is an even number. So, the median is:
![Median = \frac{1}{2}(n+1)](https://tex.z-dn.net/?f=Median%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28n%2B1%29)
![Median = \frac{1}{2}(14+1)](https://tex.z-dn.net/?f=Median%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2814%2B1%29)
![Median = \frac{1}{2}(15)](https://tex.z-dn.net/?f=Median%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2815%29)
![Median = 7.5th](https://tex.z-dn.net/?f=Median%20%3D%207.5th)
This implies that the median is the average of the 7th and 8th item.
Next, is to order the data (in ascending order): <em>36.45, 38.03, 38.19, 39.17, 39.44, 40.1, 40.2, 40.2, 40.3, 43.1, 43.2, 43.4, 43.4, 43.4.</em>
The 7th and 8th items are: 40.2 and 40.2
The median is:
![Median = \frac{1}{2}(40.2 + 40.2)](https://tex.z-dn.net/?f=Median%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2840.2%20%2B%2040.2%29)
![Median = \frac{1}{2}*80.4](https://tex.z-dn.net/?f=Median%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A80.4)
![Median =40.2](https://tex.z-dn.net/?f=Median%20%3D40.2)
Solving (c): The mode
43.4 has the highest number of occurrence.
So:
![Mode = 43.4](https://tex.z-dn.net/?f=Mode%20%3D%2043.4)
Your answer would be 6 cm