Answer:
6:12
Step-by-step explanation:
Add 1+2=3
18/3=6
6x1=6
6x2=12
Out it back in the ratio
6:12
Reflection over x-axis
hope that helps
Answer: Our required probability would be 0.9641.
Step-by-step explanation:
Since we have given that
Number of hours he works a day = 8
So, Number of minutes he worked in a day = 
Number of calls = 220
So, Average 
Standard deviation 
Mean = μ = 2.0 minutes
Standard deviation = σ = 1.5 minutes
Using the normal distribution, we get that

So, the probability that Albert will meet or exceed his quota would be

Hence, our required probability would be 0.9641.
Answer:
Continuous random variable
Step-by-step explanation: