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Anna71 [15]
3 years ago
7

(This question is related to the picture question)

Mathematics
1 answer:
UNO [17]3 years ago
6 0

Answer:

5. f(x) = 10,000 (1.5)^x

Step-by-step explanation:

==>>We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.

  • Let's test it

Initial: 10,000

After 1 year

10,000 + (.5*10000)

10,000 + 5000 = 15,000

--

After 2 years

15,000 + (.5*15000)

15,000 + 7500 = 22,500

--

Let's try our equation.

f(x) = 10,000 (1.5)^x

x=2

10,000(1.5)^2

10,000(2.25) = 22,500

*Edit: I just seen that the question is related to the picture question

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8 0
3 years ago
PLEASE HELP!
bezimeni [28]

Answer:

The whole candy is 400

The amount of red candies is unknown , let it be represented by y

To find the amount of red candy :

y= (32% of 400)

y = 32/100 × 400

y = 32×400/100

y= 32×4

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8 0
3 years ago
Branden and Pete both play running back. Branden carries the ball 75 times for 550 yards and Pete had 42 carries for 380 yards w
mars1129 [50]

Answer:

Pete runs farther per carry.

Step-by-step explanation:

Given:

Branden and Pete both play running back.

Branden carries the ball 75 times for 550 yards.

Pete had 42 carries for 380 yards

Question asked:

Who runs farther per carry ?

Solution:

First of all we find each boy's distance covered per carry:-

<u>For Branden</u>

Branden carries the ball 75 times for = 550 yards.

Branden carries the ball 1 time for = \frac{550}{75} =7.34\ yard

<u>For Pete </u>

Pete carries 42 times for = 380 yards

Pete carries 1 time for = \frac{380}{42} =9.05\ yards

As Pete runs 9.05 yards for 1 carry while Branden runs 7.34 yards for 1 carry, hence Pete runs farther per carry.

3 0
3 years ago
Quadrilateral
Solnce55 [7]

Step-by-step explanation:

because I don't know how much more I am going to be out with me I'm down if I could watch it with you for this information and the best way to reactor to be out of my account i

6 0
3 years ago
The foal has a mass of 100kg and is moving at 8m/s along the beach what is the kinetic energy (KE) of the foal​
AleksAgata [21]
<h2>>> Answer </h2>

__________

Ek = ½mv²

Ek = ½•100•8²

Ek = ½•100•64

Ek = ½•6,400

Ek = 3,200j

5 0
3 years ago
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