The bus traveled<span> at an </span>average speed<span> of </span>40 km/h<span> and </span>she<span> - 2385764. ... </span>bus<span> from </span>her home<span> to the </span>bank <span>and </span>then walked back<span> to </span>her home along<span> the </span>same route<span>. ... To determine the time, x, that it </span>took Talia<span> to</span>walk home<span>, </span>she<span> used the equation </span>40(0.9<span> – x) = 5x. 1 ... Therefore, it </span>took Talia<span> 0.8 </span>hour<span> to </span>walk home<span> or 48 minutes</span>
The height of the object after 1 sec is 284 feet
<h3>Equation of height of an object</h3>
Given the equation of height of an object expressed as:
h(t) = -16t^2 + 300t
We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression
h(t) = -16t^2 + 300t
h(1) = -16(1)^2 + 300(1)
h(1) = -16 + 300
h(1) = 284ft
Hence the height of the object after 1 sec is 284 feet
Learn more on maximum height here: brainly.com/question/12446886
Answer:
The answer is 40 sq. units
That is: 1/2×b×h (formula for area of triangle)
1/2×10×8
= 40
Answer:
226.084 sq.m.
Step-by-step explanation:
Radius of circle = 18.6 cm
Area of sector = 
Area of sector = 
Area of sector = 
Area of triangle = 
a = OA = radius = 18.6 cm
b = OB = radius = 18.6 cm
x =123 °
Substitute the values in the formula
Area of triangle = 
Area of triangle = 
So, Area of shaded region = Area of sector - Area of triangle
=
=
Hence the area of the shaded region is 226.084 sq.m.
