Solve the inequality 7(x+2)-5>3(x-1)

Find the distance between (-3, -11) and (8, -42)

Marianna [84]

Answer:

32.8937 units

Step-by-step explanation:

So, we can imagine this as a right triangle with a length of 11 (THe change of the X's) and the height being 31 (Change of the Y's)

Then we use pythagorean therom to find the hypotenuse (the length)

11^2 + 31^2 = c^2

121+961 = C^2

1082 = c^2

32.8937units

3 0

2 years ago

Please help! I’ll give brainliest!!

inn [45]

Answer:

1.a part, share, or number considered in comparative relation to a whole.

1/3 = 2/6

2.If a proposition is true, then we say it has a truth value of "true"; if a proposition is false, its truth value is "false". For example, "Grass is green", and "2 + 5 = 5" are propositions. The first proposition has the truth value of "true" and the second "false".

3.

Don't confuse cross multiplication with cross cancellation. You use cross cancellation to make multiplying fractions easier. Set the two cross products equal to each other. 1 · 2 = 2 and 0.5 · f = 0.5f.

5 0

3 years ago

mrs perry shares out 30 biscuits between gemma and zak in the ration 1:4 how many biscuits does each child get

Aloiza [94]

Gemma gets 6 Biscuits and Zak gets 24 Biscuits.

8 0

3 years ago

A manufacturer produces crankshafts for an automobile engine. the crankshafts wear after 100,000 miles (0.0001 inch) is of inter

Daniel [21]

Part A:

Significant level:

α = 0.05

Null and alternative hypothesis:

h0 : μ = 3 vs h1: μ ≠ 3

Test statistics:

$z= \frac{\bar{x}-\mu}{\sigma/\sqrt{n}} \\ \\ = \frac{2.78-3}{0.9/\sqrt{15}} \\ \\ = \frac{-0.22}{0.2324} =-0.9467$

P-value:

P(-0.9467) = 0.1719

Since the test is a two-tailed test, p-value = 2(0.1719) = 0.3438

Conclusion:

Since the p-value is greater than the significant level, we fail to reject the null hypothesis and conclude that there is no sufficient evidence that the true mean is different from 3.

Part B:

The power of the test is given by:

$\beta=\phi\left(Z_{0.025}+ \frac{3-3.25}{0.9/\sqrt{15}}\right) -\phi\left(-Z_{0.025}+ \frac{3-3.25}{0.9/\sqrt{15}}\right) \\ \\ =\phi\left(1.96+ \frac{-0.25}{0.2324} \right)-\phi\left(-1.96+ \frac{-0.25}{0.2324} \right)=\phi(0.8842)-\phi(-3.0358) \\ \\ =0.8117-0.0012=0.8105$

Therefore, the power of the test if μ = 3.25 is 0.8105.

Part C:

The sample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is obtained as follows:

$1-0.9=\phi\left(Z_{0.025}+ \frac{3-3.75}{0.9/\sqrt{n}}\right) -\phi\left(-Z_{0.025}+ \frac{3-3.75}{0.9/\sqrt{n}}\right) \\ \\ \Rightarrow0.1=\phi\left(1.96+ \frac{-0.75}{0.9/\sqrt{n}}\right)-\phi\left(-1.96+ \frac{-0.75}{0.9/\sqrt{n}} \right) \\ \\ =\phi\left(1.96+(-3.2415)\right)-\phi\left(1.96+(-3.2415)\right) \\ \\ \Rightarrow\frac{-0.75}{0.9/\sqrt{n}}=-3.2415 \\ \\ \Rightarrow\frac{0.9}{\sqrt{n}}=\frac{-0.75}{-3.2415}=0.2314 \\ \\ \Rightarrow\sqrt{n}=\frac{0.9}{0.2314}=3.8898$

$\Rightarrow n=(3.8898)^2=15.13$

Therefore, the sample size that would be required to detect a true mean of 3.75 if we wanted the power to be at least 0.9 is 16.

8 0

3 years ago

Rosa is building a guitar. The second fret is 33.641 mm from the first fret. The third fret

Olegator [25]

Answer:

Step-by-step explanation:

3 0

3 years ago

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