A city manage must predict the population of the city between the years 2000

Helpppppppppppppppppppppppp

kupik [55]

Answer:

$360\ cm^2$

Step-by-step explanation:

Step 1: Determine the area of the bottom rectangle

$A = l * w$

$A = 10\ cm * 12\ cm$

$A = 120\ cm^2$

Step 2: Determine the area of the back rectangle

$A = l * w$

$A = 10\ cm * 5\ cm$

$A = 50\ cm^2$

Step 3: Determine the area of the top rectangle

$A = l * w$

$A = 10\ cm * 13\ cm$

$A = 130\ cm^2$

Step 4: Determine the area of the triangle

$A = \frac{h*b}{2}$

$A = \frac{5\ cm * 12\ cm}{2}$

$A = \frac{60\ cm^2}{2}$

$A = 30\ cm^2$

Step 5: Determine the surface area

$120\ cm^2 + 50\ cm^2 + 130\ cm^2 + 2(30\ cm^2)$

$360\ cm^2$

Answer: $360\ cm^2$

4 0

2 years ago

Robin can mow a lawn in 3 hours, while Brady can mow the same lawn in 4 hours. How many hours would it take for them to mow the

BaLLatris [955]

The answer is twelve sevenths (12/7)

x - the job
t - time to do the job x

Robin can mow a lawn in 3 hours: x/3 * t
Brady can mow the same lawn in 4 hours: x/4 * t

If they work together, the total work will be the sum of their speeds:
x = x/3 * t + x/4 * t = (x/3 + x/4)*t = (4x/12 + 3x/12) * t = 7x/12 * t

x = 7x/12 * t

Divide both sides by x:
x/x = 7x/12 * t/x
1 = 7/12 t
t = 1 : 7/12
t = 12/7

5 0

3 years ago

The equation d=rt is used to calculate distance, rate, or time, where dd is the distance (in meters), r is the rate (in meters p

MAVERICK [17]

We know derrick walks 145 m/min to get the other we simply divide how far they went in how much time
Tomas: 1200/8= 150 m/min
Becky: 1400/10= 140m/min
therefore Tomas is the fastest walker so we will write the equation based on his speed
y = 150x
you should start at the origin (0,0) and got up 150 meters for and over 1 for every minute they run!

8 0

3 years ago

Read 2 more answers

Write an expression to find how many times Jason will blink in 60 minutes if he continues to blink 19 times a minute.

Sauron [17]

My brain can’t comprehend this

4 0

3 years ago

Need help for number 4 please

Marina CMI [18]

Answer:

Step-by-step explanation:

4) ΔSTW ≅ ΔBFN . So, corresponding parts of congruent triangles are congruent.

a) BN = SW d) m∠W = m∠N

BN = 9 cm m∠W = 82°

b) TW = FN e) m∠B = m∠S

TW = 14 cm m∠B = 67°

c) BF = ST f) m∠B + m∠N + m∠F = 180°

BF = 17 cm 67 + 82 + m∠F = 180

149 + m∠F = 180

m∠F = 180 - 149

m∠F = 31°

5) ΔUVW ≅ ΔTSR

UV = TS

12x - 7 = 53

12x = 53+7

12x = 60

x = 60/12

x = 5

UW =TR

3z +14 = 50

3z = 50 - 14

3z = 36

z = 36/3

z = 12

SR =VW

5y - 33 = 57

5y = 57 + 33

5y = 90

y = 90/5

y = 18

7) ΔPHS ≅ ΔCNF

∠C = ∠P

4z - 32 = 36

4z = 36 + 32

4z = 68

z = 68/4

z = 17

∠H = ∠N

6x - 29 = 115

6x = 115 + 29

6x = 144

x = 144/6

x = 24

∠P + ∠H + ∠S = 180 {Angle sum property of triangle}

36 +115 + ∠S = 180

151 + ∠S = 180

∠S = 180 - 151

∠S = 29°

∠F = ∠S

3y - 1 = 29

3y = 29 + 1

3y = 30

y = 30/3

y = 10

8) ΔDEF ≅ ΔJKL

DE = 18 ; EF = 23

DF = 9x - 23

JL= 7x- 11

DF = JL {Corresponding parts of congruent triangles}

9x - 23 = 7x - 11

9x - 7x - 23 = -11

2x - 23 = -11

2x = -11 + 23

2x = 12

x = 12/2

x = 6

JK = DE {Corresponding parts of congruent triangles}

3y - 21 = 18

3y = 18 + 21

3y = 39

y = 39/3

y = 13

4 0

3 years ago