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Digiron [165]
2 years ago
10

Solve the system using a matrix. NEED HELP ASAP!!:):)

Mathematics
2 answers:
icang [17]2 years ago
7 0

1,-4 sorry if wrong :(

natali 33 [55]2 years ago
4 0

Step-by-step explanation:

1.3x+2y=13

3x+2y+-2y=13+-2y

3x=-2y +13

3x/3=2y+13/3

The answer is x= -2/3 y+13/3

2.x= -2/3 y+ -1/3 z +13/3

3.x= -1/5 y +9/5

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Given the piecewise function shown, find the value of h(–6). A) 1 B) 26 C) -23 D) -6
kirza4 [7]

Answer:

-22

Step-by-step explanation:

Which part of the function is valid when x = -6

The first part

h(-6) = 4x+2 and let x = -6

        =4(-6) +2

        = -24 +2

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5 0
3 years ago
Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t
slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

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3 years ago
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Answer:

B

Step-by-step explanation:

Because 15-4=11

and both angles are equal

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What is the area of the circle? *
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