Answer:
In this question if g and h is constant then;
111 = 14g
14g = 111
g = 111/14
g = 27.7 ~ 28
And also,
13.65 = h + 4.88
h + 4.88 = 13.65
h = 13.65 - 4.88
h = 8.77
Hope it helps!
Answer:
all the time
Step-by-step explanation:
<span>Answer:
MgF2 ====⇒ Mg+2 + 2F-
Ksp = [Mg+2][F-]^2
Let S = molar solubility of MgF2
[Mg+2] = S ; [F-] = 2s
Since the [F-] is initially 0.40 M, then [F-] = 0.40 + 2S
6.4 x 10^-9 = (S) (0.40 + 2S)^2 ; one can neglect the 2S in the 0.40 + 2S expression since it is very, very small compared to the 0.40 already present.
6.4 x 10^-9 = S(0.40)^2
S = 4.0 x 10^-8
Molar solubility = 4.0 x 10^-8</span>
Answer:
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Step-by-step explanation:
