What is the simplest form of the square root 1764

Mathematics

2 answers:

melisa1 [442]3 years ago

6 0

42 is the square root

Ludmilka [50]3 years ago

5 0

Answer:

Hope this helps Buddy!

- Courtney

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Michele correctly solved a quadratic equation using the quadratic formula as shown below.

Fofino [41]

Answer:

The original equation must have been:

$7x^{2} -5x-2=0$

Step-by-step explanation:

A quadratic equation is in the form of :

$ax^{2} +bx+c=0$

And it is solved in the form of :

$x=\frac{-b+\sqrt{b^{-4ac} } }{2a}$ and $x=\frac{-b-\sqrt{b^{-4ac} } }{2a}$

Now the given equation is :

$x=\frac{-(-5)+-\sqrt{(-5)^{2} -4(7)(-2)} }{2(7)}$

We can see that here;

a = 7

b = -5

c = -2

So, the original equation must have been:

$7x^{2} -5x-2=0$

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3 years ago

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leva [86]

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3 years ago

Read 2 more answers

Solve each system by substitution. -5x + 3y = 3 and -4x + y = 1

taurus [48]

$\left\{\begin{array}{ccc}-5x+3y=3\\-4x+y=1&|\text{add 4x to both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}-5x+3y=3\\y=4x+1&(*)\end{array}\right\\\\\text{Substitute }\ (*)\ \text{to the first equation}\\\\-5x+3(4x+1)=3\qquad\text{use distributive property}\\\\-5x+(3)(4x)+(3)(1)=3\\\\-5x+12x+3=3\qquad\text{subtract 3 from both sides}\\\\7x=0\qquad\text{divide both sides by (-5)}\\\\\boxed{x=0}\\\\\text{Substitute the value of x to}\ (*):\\\\y=4(0)+1\\y=0+1\\\boxed{y=1}\\\\Answer:\ x=0\ and\ y=1.$