Given the height of the tree and the angle of elevation from point B, the distance between the tree is from point B is approximately 70ft.
<h3>What is the distance between the tree and point B?</h3>
Given the data in the question;
- Height of tree opposite angle of elevation = 34ft
- Angle of elevation θ = 26°
- Distance between tree and point B| Adjacent = ?
Since the scenario form a right angle triangle, we use trig ratio.
tanθ = Opposite / Adjacent
tan( 26° ) = 34ft / x
We solve for x
x = 34ft / tan( 26° )
x = 34ft / 0.4877
x = 70ft
Given the height of the tree and the angle of elevation from point B, the distance between the tree is from point B is approximately 70ft.
Learn more about trigonometric ratio here: brainly.com/question/28038732
#SPJ1
Depth=15
x=(height(h)*width(w)*hypotenuse(y))/2
x=(3*4*5)/2=(60/2)=30
y=(x(x-h)(x-w)(x-y))^(1/2)
f=(-h^4+2(hw)^2+2(wy)^2-w^4+2(hy)^2-y^4)^(1/2)
f=(-3^4+2(3*4)^2+2(4*5)^2-4^4+2(3*5)^2-5^4)^(1/2)
f=576^(1/2)
f=24
Surface Area= 2f(.5)+(h+w+y)*depth
192=depth*(3+4+5)+24(.5)
180=(3+4+5)*depth
180=(12)(depth)
15=depth
Answer:
wives
sacks
cats
kits
Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.
Step-by-step explanation:
wives
If each of the "x" wives has "x" sacks, so the number of sacks is:
sacks
If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:
cats
If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:
kits
Horizontal
The Axes. The independent variable belongs on the x-axis (horizontal line) of the graph and the dependent variable belongs on the y-axis
Answer: 942
Step-by-step explanation: 20 x 3.14 = 62.8 62.8 x 15 = 942
