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Firdavs [7]
3 years ago
14

Your checking account has a balance of –$82. You deposit $59. How much more do you need to deposit to have a balance of $50? The

answer is 73 but..... explain how you got that answer in detail.
Mathematics
2 answers:
Mice21 [21]3 years ago
6 0
E importance of reconciling a bank<span> statement. ... Demonstrate the ability to </span>balance<span> a checkbook and ... She only </span>needs<span> $25, </span>but<span> ... Alexis </span>has<span> no idea how ... As a customer, </span>you should<span> be familiar with the fees at </span>your bank<span>. If </span>you<span> ... a safe place until </span>you get<span> home; then use it to record how</span>much you<span> removed from.</span>
Semmy [17]3 years ago
6 0
If you had -82 dollars in debt, then deposited 59, you would be at -23 dollars in debt. At this point, you want to be at 50 dollars positive. To do this you would need to balance the 23 dollars (by adding 23 dollars). After balancing you'd be at 0. Then deposit another 50 (so after the first deposit you'd have deposited 
50+23 dollars, this equals 73 dollars). So 73 dollars is how much you need to deposit after the initial 59. 
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Victoria is interested in opening her own candy store. She has researched and found that of the 14 stores she investigated, the
Anna71 [15]

Answer:

99% confidence interval for the average start up cost is [76.575 , 123.425].

Step-by-step explanation:

We are given that of the 14 stores Victoria investigated, the average start up cost is 100 thousand dollars with a standard deviation of 29.1 thousand dollars.

So, the pivotal quantity for 99% confidence interval for the population average start up cost is given by;

           P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample average start up cost = 100 thousand dollars

             \sigma = sample standard deviation = 29.1 thousand dollars

             n = sample of stores = 14

             \mu = population average start up cost

<em>So, 99% confidence interval for the average start up cost, </em>\mu<em> is ;</em>

P(-3.012 < t_1_3 < 3.012) = 0.99

P(-3.012 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 3.012) = 0.99

P( -3.012 \times {\frac{s}{\sqrt{n} } < {\bar X - \mu} < 3.012 \times {\frac{s}{\sqrt{n} } ) = 0.99

P( \bar X-3.012 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +3.012 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-3.012 \times {\frac{s}{\sqrt{n} } , \bar X +3.012 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 100-3.012 \times {\frac{29.1}{\sqrt{14} } , 100+3.012 \times {\frac{29.1}{\sqrt{14} } ]

                                                 = [76.575 , 123.425]

Therefore, 99% confidence interval for the population average start up cost for a candy store is [76.575 , 123.425].

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