81 divided by 37.5 equals 2.16, 2.16 would be equivalent to 1% so to find 100% we simbly multiply 2.16 by 100, 2.16 multiplied by 100 equates to 216, so the Baker is making 216 muffins.
If this is a word problem, put it into your own words in case of getting in trouble.
I hope this helped, have an awesome day!!
(brainliest is always appreciated)
Answer:

Step-by-step explanation:
Given




Required
The perimeter
To do this, we first calculate the side lengths using distance formula

So, we have:








The perimeter is:



Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
<h3>Answer: 7 goes in the blank space</h3>
The range of values for x is 2 < x < 7
========================================
Explanation:
The hinge theorem says that the larger the opposite side is, the larger the angle will be.
AD = 11, DC = 8
Since AD > DC, this means angle ABD > angle DBC.
--------
angle ABD > angle DBC
20 > 4x-8
20+8 > 4x-8+8 ... add 8 to both sides
28 > 4x
4x < 28 ... flip both sides and the inequality sign
4x/4 < 28/4 ... divide both sides by 4
x < 7
--------
At the same time, the angle 4x-8 cannot be 0 or negative.
So we say 4x-8 > 0. Let's solve this for x.
4x-8 > 0
4x-8+8 > 0+8 ... add 8 to both sides
4x > 8
4x/4 > 8/4 ... divide both sides by 4
x > 2
2 < x ... flip both sides and the inequality sign
--------
We have 2 < x and x < 7. Both of these combine to the compound inequality 2 < x < 7
We can pick any value between 2 and 7 as long as we dont pick x = 2 or we dont pick x = 7.