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3 years ago

When do you need to compare real-world numbers?

1 answer:

4 0

Real world numbers are most likely to be compared in the settings wherein their functions are more effective and accurate than when they are not. Aspects such as accounting reasons and others are crucial in determining the most accurate results when it comes to these numbers.

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Use the rectangle below as an example

velikii [3]

Answer:

sorry man or man drawing a little more about the job than the rest on any of these

5 0

2 years ago

A student ran out of time on a multiple choice exam and randomly guessed the answers for two problems. Each problem had 5 answer

choli [55]

Answer:

there is a 64% chance that the student got both problems wrong

a 32% chance that they got only 1 correct

and a 4% chance that they got both correct

Step-by-step explanation:

There are 25 total possible combinations of answers, with 8 possible combinations where the student would get 1 answer right, and 1 combination where the student would get both answers correct.

$25-9=16$

$\frac{16}{25} =\frac{x}{100}$

$\frac{64}{100}$

$64$ %

$\frac{8}{25} =\frac{y}{100}$

$\frac{32}{100}$

$32$ %

$\frac{1}{25} =\frac{z}{100}$

$\frac{4}{100}$

$4$ %

3 0

3 years ago

What numbers rounded to 200,000 when rounded to the nearest hundred thousand

Elanso [62]

Answer:

The answer would be 150,000 to 249,999

7 0

3 years ago

Please help me out!!!

Gala2k [10]

Answer:

Step-by-step explanation:

Use the Pythagorean theorem.

a^2 + 6^2 = 10^2

a^2 + 36 = 100

a^2 = 64

a = 8

5 0

3 years ago

A professor believes the students in a statistics class this term are more creative than most other students attending the unive

djverab [1.8K]

Answer:

Correct option: B

Step-by-step explanation:

The professor can perform a One-mean t-test to determine whether the average score of the students in his class is more than the average score of all the students attending university.

A t-test will be used instead of the z-test because the population standard deviation is not provided instead it is estimated by the sample standard deviation.

The hypothesis for this test can be defined as follows:

H₀: The average score of the students in his class is not more then the entire university, i.e. μ ≤ 35.

Hₐ: The average score of the students in his class is more then the entire university, i.e. μ > 35.

Given:

$\bar x=40\\SE_{\bar x}=1.63$

The test statistic is:

$t=\frac{\bar x-\mu}{SE_{\bar x}}=\frac{40-35}{1.63}=3.0674\approx3.07$

Thus, the correct option is (B).

4 0

3 years ago