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Blababa [14]
3 years ago
8

An equation that represents this graph is y= 0.6x+1

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

There is no graph.

Step-by-step explanation:

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What is the equation of the line that is parallel to y−5=−13(x+2) and passes through the point (6,−1)?
BartSMP [9]

Answer:

y=-13x + 78 I'm not sure what's up with those answer choices though

7 0
3 years ago
The nth term of a sequence is 2n-1.
damaskus [11]

Answer: 25, 31 and 37

Step-by-step explanation:

(2n-1)= 19, 21, 23, 25, 27, 29, 31, 33, 35, 37

(3n+1)= 19, 22, 25, 28, 31, 34, 37,

5 0
3 years ago
42. A cylinder has a base of 36 π in² and a volume of 432π in³. What is the surface area of the same cylinder? *
faust18 [17]

Answer:

216π in²

Step-by-step explanation:

Base area = π × r²

36 π = π × r²

r² = 36

r = 6

Volume = base area × height

432 π = 36 π × height

height = 12

Surface area:

2 × π × r × (r + h)

2π × 6 × (6 + 12)

216π

8 0
3 years ago
Please at least help me cause I have no idea
Blababa [14]

Answer:

Solving the given formula for v2 gives us:

a(t_2-t_1)+v_1 = v_2

Step-by-step explanation:

Solving an equation for a particular variable means that the variable has to be isolated on one side of the equation.

Given equation is:

a = \frac{v_2-v_1}{t_2-t_1}

Multiplying both sides by t2-t1

(t_2-t_1) . a = \frac{v_2-v_1}{t_2-t_1} . (t_2-t_1)\\a(t_2-t_1) = v_2-v_1

Adding v1 to both sides of the equation

a(t_2-t_1)+v_1 = v_2-v_1+v_1\\a(t_2-t_1)+v_1 = v_2

Hence,

Solving the given formula for v2 gives us:

a(t_2-t_1)+v_1 = v_2

8 0
3 years ago
The table of values represents a quadratic function. What is the average rate of change for f(x) from x = 0 to x = 10 ? Enter yo
Elena-2011 [213]
By definition we have that the average rate of change is given by:
 AVR = (f (x2) - f (x1)) / (x2 - x1)
 Substituting the values we have:
 AVR = (204 - (-6)) / (10 - 0)
 Rewriting we have:
 AVR = (204 + 6) / (10 - 0)
 AVR = 210/10
 AVR = 21
 Answer:
 
the average rate of change for f (x) from x = 0 to x = 10 is:
 
AVR = 21
8 0
4 years ago
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