This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get
i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:
where 
is a compact way to indicate both solutions 
and 
, while 
are the coefficients of the quadratic equation, i.e. we consider the polynomial 
.
So, in your case, we have 
Plug those values into the formula to get
So, the two solutions are
Steps to solving equations:
Simplify/combine the like terms
Isolate the variable (Get the variable on one side
Solve for the variable
-2y - 7 + 5y = 13 - 2y Simplify/Combine terms
3y -7 = 13 - 2y Isolate variable by adding 2y to both sides
5y - 7 = 13 Add 7 to both sides to get y alone on one side
5y = 20 Divide by 5 on both sides to solve for y
y = 4
You can check your answer by replacing y with 4 in the original equation.
It equals 23 degrees Fahrenheit. So -5c=23f
Answer:
I don't know where those answers are coming from, but I got:
23s - 145
Point D will pass from (1,-2) to (-1,2)
The second choice is the correct one.
