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3 years ago

-6 + (-2) + 5= ? Help would really be appreciated!! :)

Mathematics

2 answers:

lozanna [386]3 years ago

6 0

Answer:

-6 + (-2) + 5 = -3

(Hope this helps! Btw, I am the first to answer. Brainliest pls! :D)

kvasek [131]3 years ago

4 0

Answer:

-3

Step-by-step explanation:

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8 is to 64 as 2 is to x

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Using descriptive statistics, you have found out that it takes an average of 40 minutes to complete a mid-term examination in IS

choli [55]

Answer:

b. exam completion time is negatively skewed

Step-by-step explanation:

A data distribution is said to be negatively skewed when <em>median</em> value of the distribution is higher than the <em>average</em> value of the distribution.

In this example

average mid-term completion time is 40 minutes

median mid-term completion time is 55 minutes.

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3 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the expect

Softa [21]

Answer:

For Australia: 22,044,350

For China: 1,545,744,200

For Mexico: 145,507,500

For Zaire: 92,237,875

Step-by-step explanation:

For Australia: Population in 2000 is 19,169,000 and it is increasing steadily at a rate of 0.6% per year.

Therefore, the population in the year 2025 will be

$19169000[1+\frac{0.6 \times 25}{100} ]= 22,044,350$ (Answer)

For China: Population in 2000 is 1,261,832,000 and it is increasing steadily at a rate of 0.9% per year.

Therefore, the population in the year 2025 will be

$1261832000[1+\frac{0.9 \times 25}{100} ]= 1,545,744,200$ (Answer)

For Mexico: Population in 2000 is 100,350,000 and it is increasing steadily at a rate of 1.8% per year.

Therefore, the population in the year 2025 will be

$100350000[1+\frac{1.8 \times 25}{100} ]= 145,507,500$ (Answer)

For Zaire: Population in 2000 is 51,965,000 and it is increasing steadily at a rate of 3.1% per year.

Therefore, the population in the year 2025 will be

$51965000[1+\frac{3.1 \times 25}{100} ]= 92,237,875$ (Answer)

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3 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$