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timama [110]
3 years ago
10

-3 (2-x)=6x solve the equations ​

Mathematics
1 answer:
defon3 years ago
6 0

Answer:

x=-2

Step-by-step explanation:

- 3 \times (2 - x) = 6x

- 6 + 3x = 6x

- 6 = 3x

-  \frac{6}{3}  = x

- 2 = x

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Bryan owes Jennifer $15 he has $20 in his wallet use absolute value to decide if Bryan has enough money to pay Jennifer
Elina [12.6K]
Bryan does indeed have enough money to pay back Jennifer.
We have the 2 numbers -15 and 20. The absolute values of those numbers are 15 and 20.

All we have to do is subtrace 15 from 20. We have the result of positive 5, meaning Bryan will still have $5 left over.
5 0
3 years ago
Can anyone plz help me
yaroslaw [1]

Answer:

They multiplied the exponents instead of adding.

Step-by-step explanation:

Essentially, 2^2 x 2^3 is (2)(2) x (2)(2)(2) which is 5, not 6

8 0
3 years ago
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What is the 82nd term of the sequence below?
AlexFokin [52]
The rule to find the term is: y=225-4x
you want to know the 82nd term which occurs when x=82 therefore
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82nd term = -103
4 0
3 years ago
A sample of salary offers (in thousands of dollars) given to management majors is: 48, 51, 46, 52, 47, 48, 47, 50, 51, and 59. U
balu736 [363]

Answer:

Step-by-step explanation:

number of samples, n = 10

Mean = (48 + 51 + 46 + 52 + 47 + 48 + 47 + 50 + 51 + 59)/10 = 49.9

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (48 - 49.9)^2 + (51 - 49.9)^2 + (46 - 49.9)^2+ (52 - 49.9)^2 + (47 - 49.9)^2 + (48 - 49.9)^2 + (47 - 49.9)^2 + (50 - 49.9)^2 + (51 - 49.9)^2 + (59- 49.9)^2 = 128.9

Standard deviation = √128.9/10 = 3.59

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 10 - 1 = 9

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.262

Margin of error = 2.262 × 3.59/√10

= 2.57

the lower limit of this confidence interval is

49.9 - 2.57 = 47.33

the lower limit of this confidence interval is

49.9 + 2.57 = 52.47

So it is false

6 0
3 years ago
Need help what’s 7-11??
nydimaria [60]

Answer:

umm the answer to 7-11 is 69

Step-by-step explanation:

7. Always

8. sometimes

9. never

10. never

11. always

6 0
3 years ago
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