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3 years ago

PLEASE HELP!!

Mathematics

1 answer:

FrozenT [24]3 years ago

5 0

Answer:

Part A: 13 and 13, 26 and 26

Part B: yes

Step-by-step explanation:

if you distribute the 2, then it's the same expression as 6m+14. as a result, the values are all the same

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Can you help me finish this paper?? I need the answers ASAP!! Plz I will give you 79 points

Yuki888 [10]

Answer:

Step-by-step explanation:

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4 years ago

Read 2 more answers

Can someone please help me with this similar area question? I have the answer but I’m not sure how to get to it. Will make brain

Mumz [18]

Step-by-step explanation:

well there is a very simple point that you have mistaken tho:

484cm², 25cm²

Areas are defined in square cm but the radius is in cm

so:

$\sqrt{ \frac{484 {cm}^{2} }{25 {cm}^{2} } } = \frac{7.92}{r} = = = > 4.4 = \frac{7.92cm}{x} = = > x = \frac{7.92cm}{4.4} = x = 1.8cm$

and there you go

5 0

2 years ago

There are 16 people in a running race. The first 3 people to finish the race will he given prizes. How many different ways can t

rodikova [14]

Answer : 3, 360 ways

Total number of people running the race = 16

We have three slot to be filled for first, second and third

Any person can take the first position irrespective of the arrangement

one out of the 16 people can come first

out of the 15 people remaining , one person can also come second remaining 14

out of the 14 people, one person can also come third

The number of ways the gift can be awarded = 16 x 15 x 14

The nummber of ways the prizes can be awarded = 3360 ways

7 0

1 year ago

based on the simulation, what is the probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to

Triss [41]

Using the binomial distribution, supposing that 0.3 of the callers have to wait more than 8 minutes to have their calls answered, it is found that there is a 0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

For each caller, there are only two possible outcomes, either they have to wait more than 8 minutes to have their calls answered, or they do not. The probability of a caller having to wait more than 8 minutes is independent of any other caller, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$