The ten thousand value in 8920000 is 20000
The values that will round up to 20000 is any value between 15000 (inclusive) and 20000 (not inclusive)
The values that will round down to 20000 is any value between 20000 (inclusive) to 25000 (not inclusive)
For example, 16752 will round up to 20000 to the nearest ten thousand
Another example, 21251 will round down to 20000 to the nearest ten thousand.
5/54 or approximately 0.092592593
There are 6^3 = 216 possible outcomes of rolling these 3 dice. Let's count the number of possible rolls that meet the criteria b < y < r, manually.
r = 1 or 2 is obviously impossible. So let's look at r = 3 through 6.
r = 3, y = 2, b = 1 is the only possibility for r=3. So n = 1
r = 4, y = 3, b = {1,2}, so n = 1 + 2 = 3
r = 4, y = 2, b = 1, so n = 3 + 1 = 4
r = 5, y = 4, b = {1,2,3}, so n = 4 + 3 = 7
r = 5, y = 3, b = {1,2}, so n = 7 + 2 = 9
r = 5, y = 2, b = 1, so n = 9 + 1 = 10
And I see a pattern, for the most restrictive r, there is 1 possibility. For the next most restrictive, there's 2+1 = 3 possibilities. Then the next one is 3+2+1
= 6 possibilities. So for r = 6, there should be 4+3+2+1 = 10 possibilities.
Let's see
r = 6, y = 5, b = {4,3,2,1}, so n = 10 + 4 = 14
r = 6, y = 4, b = {3,2,1}, so n = 14 + 3 = 17
r = 6, y = 3, b = {2,1}, so n = 17 + 2 = 19
r = 6, y = 2, b = 1, so n = 19 + 1 = 20
And the pattern holds. So there are 20 possible rolls that meet the desired criteria out of 216 possible rolls. So 20/216 = 5/54.
<u>Original</u>
Length (L): L
width (w): w
Perimeter (P) = 2L + 2w
48 = 2(L) + 2(w)
24 = L + w
24 - L = w
*******************************************
<u>New</u>
Length (L): L + 24
width (w): 2w ⇒2(24 - L) = 48 - 2L
Perimeter (P) = 2L + 2w
112 = 2(L + 24) + 2(48 - 2L)
112 = 2L + 48 + 96 - 4L
112 = -2L + 140
-28 = -2L
14 = L
Answer: 14 m