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scoundrel [369]
4 years ago
14

Which graph represents a line with a slope of and a y-intercept equal to that of the line y = 2/3 x – 2?

Mathematics
2 answers:
qwelly [4]4 years ago
7 0
The graph would have to look like the attachment I attached to this comment. If you can't see it then the graph will go through the y-intercept of -2 and the x-intercept of 3. 

Explanation: Already we can tell that the line will go through -2 as the y-intercept. So we have to take the slope and apply it to the -2. The slope is in rise over run form. We rise 2 times. And then go to the right 3 times. We can do the same but backwards. Go down 2 times. and then go left 3 times. Do it twice in both ways and you have your line. 

choli [55]4 years ago
5 0
Its c the third graph
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Please help
OlgaM077 [116]
First, we're going to see the candies per minute that machine C packs.
150 / 2 = 75

Now that we know that machine C packs 75 candies per minute, we're going to multiply the candies machine C makes by 11 minutes.
75 x 11 = 825

We're now gonna do the same with machine D.
130 x 11 = 1430

Then we're going to find the difference between machine C and machine D, we do this because the question basically asks how much more candies can machine D pack than machine C.
1430 - 825 = 605 candies.

This is how we find our final answer.

Our answer would be D) 605.

Hope this helps!~
4 0
3 years ago
a rectangular plot of land 8m long and 6m wide.there is a flower bed in the form of a circle of radius 3m.find 1.area of land. 2
mixer [17]

Answer:

1)Area of the Land  is 48 square meters

2) Area of flower bed   is  28.26 square meter

3)Area of land excluding flower bed   is 19.74 square meters

4)cost of planting grass in land  excluding flower bed   is Rs 118.44

Step-by-step explanation:

Given:

Length of the Rectangular plot = 8m

Width of the rectangular plot =  6m

Radius of the circular flower bed = 3m

1)Area of the Land  

Area of the Rectangular plot  = Area of the Land  

Area of the Land   = length x width

Area of the Land   =  8*6

Area of the Land  = 48 square meters-----------------------------(1)

2. Area of flower bed

Area of flower bed =  4 x area of one quadrant

Area of flower bed =  area of the circle

Area of flower bed  = \pi r^2

where r is the radius

Now , substituting the values

Area of flower bed = \pi (3)(3)

Area of flower bed = 28.26 square meters-----------------------------(2)

3)Area of land excluding flower bed

Area of land excluding flower bed =  Area of the rectangular land - area of flower beds

Area of land excluding flower bed =  48 - 28.26

Area of land excluding flower bed = 19.74 square meters

4)cost of planting grass in land

Cost of planting grass per square meter = 6

Excluding the flower bed we have  19.74 square meters. to plant grass  for this 19. 74 square meters, the cost will be

=19. 74 \times 6

= Rs 118.44

6 0
4 years ago
NEED HELP ASAP PLEASE!
exis [7]
1B
2C
p/s : follow me and I will help you more about maths
5 0
3 years ago
What is 5/2 - blank = 1/3
sdas [7]

Step-by-step explanation:

taking that blank as x

5/2 -x = 1/3

the x will go to the right hand side of the equation which then would make it positive ( making x the subject) and 1/3 will come to the left hand side of the equation becoming -1/3

so the equation will become 5/2-1/3=x

solving the fraction then gives 13/6 or 2.17 as the value of x

7 0
3 years ago
What is the average rate of change for ƒ(x) = −3^x+ 79 over the interval 2 ≤ x ≤ 4?
Alinara [238K]

Answer:

The average is 124

Step-by-step explanation:

When x=2 substitute into the equation given above

-3^2+79

9+79=88...(1)

When x=4

-3^4+79

81+79=160(2)

Average of (1) and (2)

160+88/2

=248/2

=124

Therefore the average rate is 124

5 0
3 years ago
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