The mean absolute deviation for the number of hours students practiced the violin is 6.4.
<h3>What is the mean absolute deviation?</h3>
The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.
Given
Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.
The given data set is;
45, 38, 52, 58, 42
Mean Deviation = Σ|x − μ|/N.
μ = mean, and N = total number of values
|x − μ| = |45 − 47| = 2
|38− 47| = 9
|52− 47| = 5
|58− 47| = 11
|42− 47| = 5
The mean absolute deviation for the number of hours students practiced the violin is;
Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.
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Answer: 
Step-by-step explanation:
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Answer-
Answer:
poooop
Step-by-step explanation:
ahhh this is easy first eat pizza then poop easy
Answer:
The IQR is a better measure of spread for movies than it is for basketball games
Step-by-step explanation:
The Basket ball games has no outliers so we would use standard deviation as the measure of spread. The movies has an outlier so we would use IQR as the measure of spread.
Answer: Third option.
Step-by-step explanation:
According to the information given in the exercise, you can find an approximation of the the total cost in dollars of raising a child in the United States ( from birth to 17 years) given a household's annual income, with the following equation:
Where "x" represents the household's annual income in dollars.
Therefore, if the annual income is $62,500; you can identify that:
Then, in order to calculat the approximated cost to raise a child in a household with that annual income given in the exercise, you need to substitute that value of "x" into the equation and then you must evaluate in order to find the value of "y".
Through this procedure you get the following result:
