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MissTica
3 years ago
10

vitamin C comes in pills with a strength of 500 mg. how many pills would you need to make if you want a dosage 2 grams?

Mathematics
2 answers:
Anni [7]3 years ago
7 0
The answer is 4 pills.
Inessa [10]3 years ago
5 0

1 gram = 1000 mg

So, 2 gram =2000 mg , 4 pills

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Which of the following represents the graph of the equation y = 1/2x?
Natasha_Volkova [10]

Answer:

(B)

Step-by-step explanation:

Here's what we know about the equation:

- it's a positive equation

- the y-intercept is (0,0)

- the slope is 1/2

Because the equation is positive, this means the graph will increase up from left to right, so you can cross out answer choice A & D.

To find out if B or C has the right slope, you can either plug in points or use the rise/run method.

I'm going to use both methods to figure out which answer choice is correct:

<u>Plug in points method:</u>

Let's plug in the value 2 in to the equation y = 1/2x.

1/2 * 2 = 1

So at (1,2) the function should include that point.

Only B has (1,2), so that's your answer.

<u>Rise/run method:</u>

Rise/run is a method used to figure out the slope of a function or draw a function on a graph.

Rise corresponds to the numerator. In this case, 1.

Run corresponds to the denominator. In this case, 2.

We are going to start at (0,0) and go up 1 (rising 1 unit) and go 2 to the right (running 2 units). After this, we should arrive at a point on the graph.

Only answer choice B does this.

**Reminder: be careful, the each blue line on the graph ISN'T a whole number interval; it uses 1/2 intervals.

Hope that helps (●'◡'●)

8 0
2 years ago
If f is a scalar field and F, G are vector fields, then f F, F · G, and F × G are defined by the following. (f F)(x, y, z) = f(x
valentina_108 [34]

Answer:

Step-by-step explanation:

Consider curl (fF) where f is a scalar function and F is a vector function

                  F=F_{1}i +F_{2}j +F_{3}k

                     i         j          k                

curl(fF) = \frac{\partial}{\partial x}      \frac{\partial}{\partial y}      \frac{\partial}{\partial z}        

                  fF_{1}    fF_{2}    fF_{3}  

curl(fF)=i(\frac{\partial}{\partial y}(fF_{3})-\frac{\partial}{\partial z}(fF_{2}))-j(\frac{\partial}{\partial x}(fF_{3})-\frac{\partial}{\partial z}(fF_{1}))+k(\frac{\partial}{\partial x}(fF_{2})-\frac{\partial}{\partial y}(fF_{1}))

=i(\frac{\partial}{\partial y}(F_{3})+\frac{\partial}{\partial y}(f)-\frac{\partial}{\partial z}(F_{2})-\frac{\partial}{\partial z}(f))-j(\frac{\partial}{\partial x}(F_{3})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial z}(F_{1})-\frac{\partial}{\partial z}(f))+k(\frac{\partial}{\partial x}(F_{2})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial y}(F_{1})-\frac{\partial}{\partial y}(f))

curl(fF)=f(\Delta\times F)+(\Delta f)\times F

3 0
2 years ago
Simplify<br><br> -6 + { 14 + { 60 - 9 ( 1 + 3 ) { }
Lelu [443]

Answer:

32

Step-by-step explanation:

−6+14+60−9(1+3)

=32

4 0
2 years ago
Think about a standard deck of 52 playing cards. Which of the following events is mutually exclusive?
Shtirlitz [24]

Answer:

1.) Drawing a king or a queen.

Step-by-step explanation:

1.) Drawing a king or a queen.

You cannot get a king and a queen at the same time= mutually exclusive

2.) Drawing a club or a black card.

King of clubs is both a club and a black card

3.) Drawing a king or a heart.

king of hearts is both a heart and a king

4.) Drawing a face card or a heart

queen of hearts is a heart and a face card

7 0
3 years ago
Can somebody show the work and help me with number 5 please (show the work in the comments)
Arturiano [62]

Um

We need to see the chart

4 0
3 years ago
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