Question

I WILL GIVE BRAINLIEST!!! In a certain isosceles right triangle, the altitude to the hypotenuse has length 4sqrt2. What is the area of the triangle?

Answer 1

Step-by-step explanation:

${x}^{2} + {x}^{2} = {4}^{2} \\ 2 {x}^{2} = {4}^{2} \\ {x}^{2} = 8 \\ then \: the \: area \: of \: a \: triangle \: is \\ \frac{1}{2} \times {x}^{2} \\ \frac{1}{2} \times 8 \\ 4 \: square \: unit$