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den301095 [7]
3 years ago
5

If a game's price went down from $60.00 to $42.00, what is the percent of the decrease?

Mathematics
2 answers:
raketka [301]3 years ago
6 0
<span>$60.00 -  $42.00 = </span><span>$18

</span><span>$18 / $60 = 0.30 = 30%

Answer
Decrease 30%</span>
MrRissso [65]3 years ago
5 0
Hello, there!


First, we must subtract $42 from $60

$60 - $42= $18

Now we must divide $18 by $60 to figure out the percent difference in the two prices.
$18 / $60 = 0.30 

0.30 = 30%


Your answer is 30%


I hope I helped!

Let me know if you need anything else!

~ Zoe
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Answer:

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  3. <u>32 m²</u>
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Step-by-step explanation:

<u>Q1</u>

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  • 5 x 3 + 12 x 4
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2. 38, 42, 77, 47, 74, 51, 48, 41, 82, 72, 74, 129 Median: Q1 Q1: IQR: Outliers: ​
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Answer: Heyo! ;D

I think I know how to solve this...

Let me know it this helps out in any way. :D

Median: "To find the median, first you need to list them in order from least to greatest:"

38, 41, 42, 47, 48, 51, 72, 74, 74, 77, 82, 129

"Now, you count starting from both ends and count to the middle. In this case, 51 and 72 are both the medians. However, there can be only one remaining median. So, what we do is add 51 to 72, then divide the sum by 2 to end with the correct median:"

72 + 51 = 123

123 / 2 = 61.5

Outliers: "All are in a pattern, beside the one number that stands out as the outlier in the given list of numbers. 129 is the only number that isn't in sync with the pattern, hence meaning this is the outlier in the sequence of numbers above."

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2 years ago
As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

\frac{65}{e^{10k}}=C which, by exponential rules is the same as

C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

\frac{85}{65}=e^{-10k+15k} which simplifies down to

\frac{85}{65}=e^{5k}

Take the natural log of both sides to get

ln(\frac{85}{65})=5k

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

65=Ce^{10(.0536527973)}

which simplifies down to

65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

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