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Leya [2.2K]
3 years ago
13

Practice

Mathematics
1 answer:
TEA [102]3 years ago
4 0

Answer:

B. -0.5

Step-by-step explanation:

I calculated it logically

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Hw help (again)<br> hope everyone is having a wonderful day &lt;3
VladimirAG [237]

Answer:

The numbers are 8 and 6

Step-by-step explanation:

Let x and y be the two numbers

x+y = 14

x-y = 2

Add the two equations together

x+y = 14

x-y = 2

--------------

2x +0y = 16

Divide by 2

2x/2 = 16/2

x = 8

Now find y

x+y = 14

8+y =14

Subtract 8 from each side

8+y-8 =14-8

y =6

The numbers are 8 and 6

5 0
3 years ago
Read 2 more answers
Please can I help me
melamori03 [73]

Answer:

I think it's -7.73

it's -7.73 bc u add all 3 then divide -85 by 11

7 0
3 years ago
MARKING AS BRAINLIEST (
snow_lady [41]

Answer:

c=13

Step-by-step explanation:

pythagoras theorem

a^2+b^2=c^2

12^2+5^2=x^2

169=x^2

x=13

This is one of the few combination of triangle you should really memorize.

8 0
3 years ago
Read 2 more answers
Mountain climber Joe climbed to a mountain peak that was1200 feet above its base and 1500 feet east of its base. Mountain climbe
geniusboy [140]

9514 1404 393

Answer:

  Bob

Step-by-step explanation:

The "steepness," or slope, of the mountain is the ratio of height to horizontal distance to the base:

  Joe's mountain slope = 1200/1500 = 0.8

  Bob's mountain slope = 900/1000 = 0.9

Bob's mountain has a greater slope than Joe's. Bob climbed the steeper mountain.

4 0
3 years ago
Which expression is equivalent to log Subscript w Baseline StartFraction (x squared minus 6) Superscript 4 Baseline Over RootInd
lora16 [44]

The logarithmic expression \rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}} can be expressed as \rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8).

Given to us

\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}

<h3>Which expression is equivalent to \rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}} ?</h3>

To solve the problem we will use the basic logarithmic properties,

\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}

Using the logarithmic property \rm log_a\dfrac{x}{y} = log_ax-log_ay,

=\rm log_w{(x^2-6)^4} - log_w{\sqrt[3]{x^2-8}}

Using the exponential property \sqrt[m]{a^n} = a^{\frac{n}{m}},

=\rm log_w{(x^2-6)^4} - log_w(x^2-8)^{\dfrac{1}{3}}

Using the logarithmic property \rm log_aB^x = xlog_aB,

=\rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8)

Hence, the logarithmic expression \rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}} can be expressed as \rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8).

Learn more about Logarithmic Expression:

brainly.com/question/7302008

5 0
3 years ago
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