The distance is (3,4)
Simply subtract the x and y functions.
13 - 10 = 3
5 - 1 = 4
Answer:
r=15.99
Step-by-step explanation:
r=C
2π=100.48
2·π≈15.99189
Answer:
The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.
Step-by-step explanation:
To solve this question, we use the central limit theorem.
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, the sample means with size n can be approximated to a normal distribution with mean
and standard deviation 
In this problem, we have that:

The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.
Answer:
I think the length of ED should be 6