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3 years ago

A single equation representing both lines x+y=0 and x+2y = 0 is ?

Mathematics

1 answer:

kolbaska11 [484]3 years ago

4 0

Answer:

The single equation is $y = 0$

Step-by-step explanation:

We are given the following system of equations:

$x + y = 0$

$x + 2y = 0$

From the first equation:

$x = -y$

Replacing in the second equation:

$-y + 2y = 0$

$y = 0$

The single equation is $y = 0$

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Using the t-distribution, it is found that the 99% confidence interval for the difference is (0.058, 3.462).

We are given the standard deviation for the samples, hence, the t-distribution is used to solve this question.

The standard errors are given by:

$s_A = \frac{1.79}{\sqrt{18}} = 0.4219$

$s_B = \frac{1.95}{\sqrt{18}} = 0.4596$

For the distribution of differences, the mean and the standard error are given by:

$\overline{x} = \mu_A - \mu_B = 23.95 - 22.19 = 1.76$

$s = \sqrt{0.4219^2 + 0.4596^2} = 0.6239$

The interval is given by:

$\overline{x} \pm ts$

The critical value for a two-tailed 99% confidence interval with 18 + 18 - 2 = 34 df is t = 2.7284.

Then:

$\overline{x} - ts = 1.76 - 2.7284(0.6239) = 0.058$

$\overline{x} + ts = 1.76 + 2.7284(0.6239) = 3.462$

The 99% confidence interval for the difference is (0.058, 3.462).

For more on the t-distribution, you can check brainly.com/question/16162795

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3 years ago

A single equation representing both lines x+y=0 and x+2y = 0 is ?​

A single equation representing both lines x+y=0 and x+2y = 0 is ?