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zimovet [89]
3 years ago
14

Please help!! 15 Points!!!!

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
6 0

Answer: 1 solution

Step-by-step explanation: 3(

7

3

x+

4

3

)−2x+8=5x+12

all numbers are are solutions

Ray Of Light [21]3 years ago
3 0

Answer:

I think it is ether A are B

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In this problem, you will use undetermined coefficients to solve the nonhomogeneous equation y′′+4y′+4y=12te^(−2t)−(8t+12) with
Zarrin [17]

First check the characteristic solution:

<em>y''</em> + 4<em>y'</em> + 4<em>y</em> = 0

has characteristic equation

<em>r</em> ² + 4<em>r</em> + 4 = (<em>r</em> + 2)² = 0

with a double root at <em>r</em> = -2, so the characteristic solution is

y_c = C_1e^{-2t} + C_2te^{-2t}

For the particular solution corresponding to 12te^{-2t}, we might first try the <em>ansatz</em>

y_p = (At+B)e^{-2t}

but e^{-2t} and te^{-2t} are already accounted for in the characteristic solution. So we instead use

y_p = (At^3+Bt^2)e^{-2t}

which has derivatives

{y_p}' = (-2At^3+(3A-2B)t^2+2Bt)e^{-2t}

{y_p}'' = (4At^3+(-12A+4B)t^2+(6A-8B)t+2B)e^{-2t}

Substituting these into the left side of the ODE gives

(4At^3+(-12A+4B)t^2+(6A-8B)t+2B)e^{-2t} + 4(-2At^3+(3A-2B)t^2+2Bt)e^{-2t} + 4(At^3+Bt^2)e^{-2t} \\\\ = (6At+2B)e^{-2t} = 12te^{-2t}

so that 6<em>A</em> = 12 and 2<em>B</em> = 0, or <em>A</em> = 2 and <em>B</em> = 0.

For the second solution corresponding to -8t-12, we use

y_p = Ct + D

with derivative

{y_p}' = C

{y_p}'' = 0

Substituting these gives

4C + 4(Ct+D) = 4Ct + 4C + 4D = -8t-12

so that 4<em>C</em> = -8 and 4<em>C</em> + 4<em>D</em> = -12, or <em>C</em> = -2 and <em>D</em> = -1.

Then the general solution to the ODE is

y = C_1e^{-2t} + C_2te^{-2t} + 2t^3e^{-2t} - 2t - 1

Given the initial conditions <em>y</em> (0) = -2 and <em>y'</em> (0) = 1, we have

-2 = C_1 - 1 \implies C_1 = -1

1 = -2C_1 + C_2 - 2 \implies C_2 = 1

and so the particular solution satisfying these conditions is

y = -e^{-2t} + te^{-2t} + 2t^3e^{-2t} - 2t - 1

or

\boxed{y = (2t^3+t-1)e^{-2t} - 2t - 1}

7 0
2 years ago
Somebody please help me?​
Natalija [7]

The events A and B are independent events, and the values of P(A) and P(B) are 7/12 and 1/2, respectively

<h3>The value of P(A)</h3>

The event A is given as:

A : Sum greater than 6

In the sample space of a roll of two dice, there are 21 outcomes that are greater than 6, out of a total of 36 outcomes

This means that:

P(A) = 21/36

Simplify

P(A) = 7/12

<h3>The value of P(B)</h3>

The event B is given as:

B : Sum is divisible by 2

In the sample space of a roll of two dice, there are 18 outcomes that are divisible by 2, out of a total of 36 outcomes

This means that:

P(B) = 18/36

Simplify

P(B) = 1/2

Hence, the probability values of P(A) and P(B) are 7/12 and 1/2, respectively

Read more about probability at:

brainly.com/question/251701

#SPJ1

5 0
1 year ago
The area of a regular heptagon can be found by breaking the heptagon into seven congruent triangles and then taking the sum of t
hichkok12 [17]

Answer:

True

Step-by-step explanation:

The area of a regular polygon is found by multiplying 1/2 times the apothem times the perimeter.  The area for a single triangle is 1/2 times the height (which is the same as the apothem of a regular polygon) times the base (which is one of the sides of the regular polygon which you are multiplying by  to find the perimeter of the polygon).

7 0
3 years ago
Read 2 more answers
Here is a rectangle ABCD.
lana66690 [7]

Answer:

32%

Step-by-step explanation:

Area of rectangle ABCD = 20 * 30 = 600 Sq cm

After increasing the length and width of the rectangle by 20% and 10% respectively.

New length = 30 + 20% of 30 = 30 + 6 = 36 cm

New width = 20 + 10% of 20 = 20 + 2 = 22 cm

Area of new rectangle = 36*22 = 792 Sq cm

Increase in area = 792 - 600 = 192 Sq cm

Percentage increase in area

= (192/600) *100

= 32%

5 0
3 years ago
Read 2 more answers
I need the answer and explain please and thank you.
Dafna11 [192]
Use cos sin and tan and looks up rules of cos sin tan and it will show you the rules and use those methods to plug into your equation
6 0
3 years ago
Read 2 more answers
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