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Ilia_Sergeevich [38]
3 years ago
14

The ratio of red cars to blue cars in a parking lot was 5:3 . If there was 40 red cars , how many blue cars were there ?

Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0
The answer is x equals 24
you set up a proportion new over old
so for red cars 40 over 5
since we don’t know the new for blue cars we’ll use x
so x over 3
we then make them equal to each other
40 x
—- = —-
5 3
cross multiply, then we get
120=5x
isolate the x by dividing 5 from both sides to get 24
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One positive number is 3 more than twice another. If their product is 629, find the numbers.
Soloha48 [4]

Answer:

17,37

Step-by-step explanation:

one number = x

The positive number = 2x + 3

x * (2x+3) = 629

x*2x + x *3 = 629

2x² + 3x - 629 = 0

2x² - 34x + 37x - 17*37 =0

2x*(x -17) + 37(x - 17) = 0

(x - 17)(2x + 37) = 0

x - 17 = 0 ;     Ignore  2x + 37 as s is a positive number

x = 17

Positive number = 2*17 +3 = 34+3 = 37

5 0
3 years ago
3/5 of an apple tree is unripe what percent of it is ripe?
trapecia [35]
If 3/5 of the tree is unripe, then 2/5 of the tree is ripe.

2/5 = 0.4

0.4 x 100 = 40% of the tree is ripe
4 0
3 years ago
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Which expression is equivalent to 7x^2-(8x-5)+(5x-3x^2)?
Anettt [7]

Answer:

your mo- (3x^5 + 8x^3) - (7x^2 - 6x^3) = 3x^5 + 8x^3 - 7x^2 + 6x^3 = 3x^5 + 14x^3 - 7x^2

Step-by-step explanation:

7 0
3 years ago
If the average grade of an English class rose from 70 to 85, what is the approximate percent increase?
ratelena [41]

Answer:

The percent increase is approximately 21%

Step-by-step explanation:

85 - 70 = 15

15/70 = 0.21

Move decimal over twice to the right and you would get 21%

I hope you have/had an amazing day<3

6 0
2 years ago
preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha
VladimirAG [237]

Answer:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

n=369

Step-by-step explanation:

1) Notation and definitions

X=40 number of the selected labourers opt for a new incentive scheme.

n=100 random sample taken

\hat p=\frac{40}{100}=0.4 estimated proportion of the selected labourers opt for a new incentive scheme.

p true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

And rounded up we have that n=369

8 0
3 years ago
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