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Volgvan
3 years ago
14

In the town of clover, 3 out of 5 citizens who are eligible to vote did so in the fall election.

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

A

Step-by-step explanation:

The amount that actually voted is irrelevant to the question because you cant use the ratio

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A population grows with an annual growth rate of 16.5 % per year. (a) what is the monthly growth rate
Shtirlitz [24]
The monthly growth rate would be 16.5% divided by 12 which is 1.3%
8 0
3 years ago
A practice law exam has 100 questions, each with 5 possible choices. A student took the exam and received 13 out of 100.If the s
Cloud [144]

Answer:

z=\frac{13-20}{4}=-1.75

Assuming:

H0: \mu \geq 20

H1: \mu

p_v = P(Z

Step-by-step explanation:

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest (number of correct answers in the test), on this case we now that:

X \sim Binom(n=100, p=0.2)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=100*0.2=20 \geq 10

n(1-p)=20*(1-0.2)=16 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=100*0.2=20

\sigma=\sqrt{np(1-p)}=\sqrt{100*0.2(1-0.2)}=4

So we can approximate the random variable X like this:

X\sim N(\mu =20, \sigma=4)

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  The letter \phi(b) is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: \phi(b)=P(z

The z score is given by this formula:

z=\frac{x-\mu}{\sigma}

If we replace we got:

z=\frac{13-20}{4}=-1.75

Let's assume that we conduct the following test:

H0: \mu \geq 20

H1: \mu

We want to check is the score for the student is significantly less than the expected value using random guessing.

So on this case since we have the statistic we can calculate the p value on this way:

p_v = P(Z

5 0
3 years ago
What is the formula for finding volume in a prism<br>​
egoroff_w [7]

Answer:

Well it’s volume formula for prism it’s V = Bh

Step-by-step explanation:

3 0
4 years ago
Paul is 4 years older than Melissa, who is 26 years older
Nuetrik [128]

Answer: Eve is 3

Melissa is 29. (3 + 26 = 29)

Paul is 33 ( 29 + 4 = 33)

3+ 29 + 33 = 65

Step-by-step explanation:

7 0
3 years ago
Can someone please help me with this problem asap? Thanks!! :))
ivolga24 [154]

Answer: \$4.34

Step-by-step explanation:

We have the following information:

Fredburguer F, milkshake M and an order of fries f costs \$3.72:

F+M+f=\$3.72 (1)

One Fredburguer is equal to a milkshake plus orders of fries:

F=M+2f (2)

Three milshakes is equal to a Fredburguer plus an order of fries:

3M=F+f (3)

And we are asked: If we have a Fredburguer, a milkshake and two orders of fries, how much do we have to pay?

F+M+2f=x (4)

Well with the first three equations we have a system of equations to solve. Let's begin by isolating F from (3):

F=3M-f (5)

Making (2)=(5):

M+2f=3M-f (6)

Isolating f:

f=\frac{2}{3}M (7)

Substituting (7) in (2):

F=M+2(\frac{2}{3}M) (8)

Isolating F:

F=\frac{7}{3}M (9)

Substituting (7) and (9) in (1):

\frac{7}{3}M+M+\frac{2}{3}M=\$3.72 (10)

Isolating M:

M=\$0.93 (11) This is the cost of a Milkshake

Substituting (11) in (7):

f=\frac{2}{3}\$0.93 (12)

f=\$0.62 (13) This is the cost of an order of frieds

Substituting (11) in (9):

F=\frac{7}{3}\$0.93 (14)

F=\$2.17 (15) This is the cost of a Fredburguer

Substituting (11), (13) and  (15) in (4):

\$2.17+\$0.93+2(\$0.62)=x (16)

Finally:

x=\$4.34 This is the cost of a Fredburguer, a milkshake and two orders of fries

8 0
3 years ago
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