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Georgia [21]
3 years ago
7

Help plz imagine attached

Mathematics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

Angle of elevation = 21.167°

Step-by-step explanation:

Given:

Horizontal distance cover by rover = 180 m

Vertical distance cover by rover = 65 m

Find:

Angle of elevation

Computation:

Using trigonometry function;

Sin θ = Perpendicular / Hypotenuse

⇒ Sin θ = Vertical distance cover by rover / Horizontal distance cover by rover

⇒ Sin θ = 65 / 180

⇒ Sin θ = 0.3611

⇒ Sin⁻¹ (0.3611) = 21.167°

Angle of elevation = 21.167°

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Find the absolute extrema of f(x) = e^{x^2+2x}f ( x ) = e x 2 + 2 x on the interval [-2,2][ − 2 , 2 ] first and then use the com
fredd [130]

f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}

f has critical points where the derivative is 0:

2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1

The second derivative is

f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}

and f''(-1)=\frac2e>0, which indicates a local minimum at x=-1 with a value of f(-1)=\frac1e.

At the endpoints of [-2, 2], we have f(-2)=1 and f(2)=e^8, so that f has an absolute minimum of \frac1e and an absolute maximum of e^8 on [-2, 2].

So we have

\dfrac1e\le f(x)\le e^8

\implies\displaystyle\int_{-2}^2\frac{\mathrm dx}e\le\int_{-2}^2f(x)\,\mathrm dx\le\int_{-2}^2e^8\,\mathrm dx

\implies\boxed{\displaystyle\frac4e\le\int_{-2}^2f(x)\,\mathrm dx\le4e^8}

5 0
3 years ago
Lincoln is measuring the angles of quadrilateral WXYZ to determine whether it is congruent to the quadrilateral below. Quadrilat
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Answer:

If quadrilateral WXYZ is congruent to quadrilateral RSTQ, then its corresponding elements are also congruent.

That is,

\angle R = 140\°= \angle W\\\angle S= 94 \° = \angle X\\\angle T= 79\° = \angle Y\\\angle Q = 47 \° = \angle Z

Also,

WX=RS\\XY=ST\\YZ=TQ\\WZ=RQ

Therefore, the right answer is None of the Above.

8 0
4 years ago
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Answer:

3x+3

Step-by-step explanation:

Perimeter

x+x+6+x-3=3x+3

8 0
4 years ago
I am so confused and im really struggling and this is the only question i need ​
icang [17]

A polynomial of degree 3 has exactly 3 solutions if we use complex numbers. If the polynomial has real coefficients and z is a complex solution, i.e., p(z)=0, the conjugate is also a solution: p(\overline{z})=0

So, in the first case, if we know that 1-i is a solution, the conjugate 1+i must be a solution as well.

So, we know all the roots: -5, 1+i, 1-i.

When you know the solutions x_1,\ x_2,\ldots,\ x_n of a polynomial, you can write the polynomial (up to multiples) as

p=(x-x_1)(x-x_2)\ldots(x-x_n)

So, in your case, we have

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You can check that indeed p(0)=10, because the constant term is 10, so, we're ok with this

The second exercise is exactly the same: the solutions -6, i, -i identify the polynomial

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In this case, P(-3)=30, so if we want P(-3)=60 we have to multiply everything by 2:

p(x)=2x^3+12x^2+2x+12

3 0
3 years ago
Matthew wants to buy a new pair of jeans. If the jeans were originally $65.00, but are on sale with a 10% discount, how much wil
sesenic [268]

10% off means the jeans will sell for 90% of the original price ( 100% - 10% = 90%)

Multiply the original price by 90%

65.00 x 0.90 = 58.50

He will pay $58.50

4 0
3 years ago
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