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nata0808 [166]
3 years ago
5

If two is added to five times a number, the result is equal to 5 more than four times the number. Find the number

Mathematics
1 answer:
Ugo [173]3 years ago
4 0

Answer:

ehehe23

Step-by-step explanation:

dgehhegeebsdhsbshshsbe

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There were 3 times as many monkeys as lions tom counted a total of 24 monkeys and lions. How many monkeys were there
arsen [322]
There where 72 monkey
8 0
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X is less than 1/4 of two dozen
vfiekz [6]

Answer: 7

Step-by-step explanation:

4 0
3 years ago
Aidan can complete a job in 5 minutes, while Joseph can complete the same job in 15
cluponka [151]

Answer:

10 minutes?

Step-by-step explanation:

Sorry if it is incorrect but what I did was I found the average of 5 minutes and 15 minutes and got 10.

Here's my problem solving explanation:

(5 + 15) / 2 = 10

3 0
3 years ago
Read 2 more answers
Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
Given: A= {(2,3), (5,1).(-3,-2), (0, 3))<br> What is the domain of A?
xxMikexx [17]

Answer:

The domain is (2,5,-3,0)

Step-by-step explanation:

we know that

For a set of ordered pairs, the first elements of each ordered pair represents the domain of the function and second elements of each ordered pair represents the range of the function.  

The domain of a function is the set of all possible values of x

In this problem we have

A= \ [(2,3), (5,1).(-3,-2), (0, 3)\ ]

therefore

The domain is (2,5,-3,0)

4 0
3 years ago
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