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3 years ago

Find an equation of a line with m=-3/8 passing through (3,4)

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

7 0

Answer:

$y=\frac{-3}{8}x + 5\frac{1}{8}$

Step-by-step explanation:

We are given;

The slope of a line as -3/8
A point through which the line passes through (3, 4)

We are required to determine the equation of the line.

Note that one way we can get the equation of a line is when we are given its slope and a point through which it passes through.

In this case;

m = -3/8

A point (3, 4)

We will take another point (x, y)

Therefore;

$\frac{y-4}{x-3}=\frac{-3}{8}$

We get;

$8(y-4)=-3(x-3)$

$8y-32=-3x+9$

Combining the like terms;

$8y=-3x+9+32$

$8y=-3x+41$

$y=\frac{-3}{8}x+5\frac{1}{8}$

Thus, the equation of the line is $y=\frac{-3}{8}x + 5\frac{1}{8}$

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Convert 88% to a fraction. a 1/8 b 22/25 c 23/50 d 22/55

Elena L [17]

Answer:

The correct answer is B 22/25

Step-by-step explanation:

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7 0

3 years ago

• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando

antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$Z = \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}$

$Z = \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}$

$Z = \frac{- 0.09}{ 0.048989 }$

$Z = - 1.84$

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0

3 years ago

Solve for x round to the nearest tenth.

lesantik [10]

Answer:

x ≈ 15.9

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

x² + 6² = 17²

x² + 36 = 289 ( subtract 36 from both sides )

x² = 253 ( take the square root of both sides )

x = $\sqrt{253}$ ≈ 15.9 ( to the nearest tenth )