Question

Find an equation of a line with m=-3/8 passing through (3,4)

Answer 1

Answer:

$y=\frac{-3}{8}x + 5\frac{1}{8}$

Step-by-step explanation:

We are given;

• The slope of a line as -3/8
• A point through which the line passes through (3, 4)

We are required to determine the equation of the line.

• Note that one way we can get the equation of a line is when we are given its slope and a point through which it passes through.

In this case;

m = -3/8

A point (3, 4)

We will take another point (x, y)

Therefore;

$\frac{y-4}{x-3}=\frac{-3}{8}$

We get;

$8(y-4)=-3(x-3)$

$8y-32=-3x+9$

Combining the like terms;

$8y=-3x+9+32$

$8y=-3x+41$

$y=\frac{-3}{8}x+5\frac{1}{8}$

Thus, the equation of the line is $y=\frac{-3}{8}x + 5\frac{1}{8}$