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Vedmedyk [2.9K]
3 years ago
7

I need help with the work and math

Mathematics
1 answer:
nexus9112 [7]3 years ago
3 0
What do you need help with ??
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2. What conjecture can you make about the eighteenth term in the pattern A, B, A, C, A, B, A, C?
slamgirl [31]

Answer:

The eighteenth term is B

Step-by-step explanation:

I could just write the pattern A B A C out until you get to the eighteenth term

A(1) B(2) A(3) C(4) A(5) B(6) A(7) C(8) A(9) B(10) A(11) C(12) A(13) B(14) A(15) C(16) A(17) B(18)

4 0
3 years ago
PLEASE HELP WITH THIS I SHALL GIVE BRAINLIEST
CaHeK987 [17]

Answer:

58

Step-by-step explanation:

can I have brainliest

6 0
3 years ago
Read 2 more answers
An orbiting satellite has seven solar cells, which function independently of each other. During a mission, each cell fails with
Makovka662 [10]
The due date is 2pm, dolololo
4 0
4 years ago
I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5
Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}

Similarly, using
\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
we derive
\frac{d}{dx}(-\sqrt{3-3x^2})
=\frac{3x}{\sqrt{3-3x^2}}

Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
3 0
3 years ago
Read 2 more answers
A sports broadcaster predicts a basketball team will score 88 point me in the next game. If the team actually scored 98 points w
gavmur [86]

Answer:

The percentage error in the prediction = 10.20%

Step-by-step explanation:

A sports broadcaster predicts a basketball team will score 88 point me in the next game.

If the team has actually scored 98 points we have to find the percentage error in the broadcaster's prediction.

The deviation of the prediction from the actual value = 98 - 88 = 10.

The formula for finding error percentage = \frac{deviation from actual value}{prediction}

                                       = \frac{10}{98} \times 100

                                       = 10.20 %

The percentage error = 10.20%

5 0
3 years ago
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