Answer:
7.3% of the bearings produced will not be acceptable
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.
So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.
Larger than 0.504
1 subtracted by the pvalue of Z when X = 0.504.
has a pvalue of 0.9938
1 - 0.9938= 0.0062
Smaller than 0.496
pvalue of Z when X = -1.5
has a pvalue of 0.0668
0.0668 + 0.0062 = 0.073
7.3% of the bearings produced will not be acceptable
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
we know that
The old account balance plus the transaction amount is equal to the new account balance
The transaction amount can be a positive number (example a deposit) or a negative number (example a withdrawal)
Part 1) Find the value of A
solve for A
subtract 432 both sides
Part 2) Find the value of B
solve for B
Rewrite
Part 3) Find the value of C
solve for C
subtract 52 both sides
<h2>
Hello!</h2>
The answer is:
The answer is the fourth option,
<h2>
Why?</h2>
Piecewise functions are functions that are composed by two or more expressions, the expression to use will depend of the domain or input that we need to evaluate.
We are given the piecewise function:
There, we know that:
We should use the first expression if the value to evaluate is less than -2.
So, for this case, the function will be:
We should use the second expression if the value to evaluate is greater or equal than 2.
So, for this case, the function will be:
Now, since we are given that the value to evaluate is -3, and its less than -2, we need to use the first expression, and evaluate it.
So, evaluating the function we have:
Hence, we have that the answer is the fourth option,
Have a nice day!
Answer:
The price of the cake is $24 and the price of the Pie is $15
Step-by-step explanation:
Given
<em>Represent price of Cake with C and Price of Pie with P</em>
Cakes sold = 8
Pies sold = 14
Required
Determine C and P
To represent the cakes and pies sold, we have the following expression
Substitute 9 + P for C
Open the bracket
Collect Like Terms
Divide both sides by 22
Recall that
<em>Hence, the price of the cake is $24 and the price of the Pie is $15</em>
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r}\\\\ -------------------------------\\\\ (x-3)^2+(y+7)^2=64\implies [x-\stackrel{h}{3}]^2+[y-(\stackrel{k}{-7})]^2=\stackrel{r}{8^2} \\\\\\ center~(3,-7)\qquad radius=8](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%0A%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%0A%5Cqquad%20%0Acenter~~%28%5Cstackrel%7B%7D%7B%20h%7D%2C%5Cstackrel%7B%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20%0Aradius%3D%5Cstackrel%7B%7D%7B%20r%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%28x-3%29%5E2%2B%28y%2B7%29%5E2%3D64%5Cimplies%20%5Bx-%5Cstackrel%7Bh%7D%7B3%7D%5D%5E2%2B%5By-%28%5Cstackrel%7Bk%7D%7B-7%7D%29%5D%5E2%3D%5Cstackrel%7Br%7D%7B8%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Acenter~%283%2C-7%29%5Cqquad%20radius%3D8)
so, the broadcast location and range is more or less like the picture below.
