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aleksandr82 [10.1K]
3 years ago
14

NEED HELP ASAP!!! An airplane flies across the country. Its distance from Portland, as a function of time, is modeled by y = 500

x. Which statement best describes the function?
Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

BRI ISH?!

Explanation:

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The answer for your question is C. $362.50

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Divide (x4 – 11x3 – 49x2 + 899x – 2506) ÷ (x – 8).
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Okay first make sure you change negative 8 to a positive 8. 
Set the problem up 8  -11 -49 899 -2506
                                    __________________
8  -11 -49   899    -2506
          -88 -1096    -1576
   ____________________
    -11 -137 -197     -4082

Your answer will be 
-11x^3 - 137x^2 - 197x - 4082
6 0
3 years ago
1) Subtract 2x + 4 from 3x - 2<br> ?
Dmitry_Shevchenko [17]

Answer:

x + 2 is the answer I think...

4 0
3 years ago
Read 2 more answers
PLEASE HELP!! NO LINKS!! GIVING 20 POINTS AWAY!!
Kruka [31]

Answer:

m∠N = 32°

NQ = 106°

When finding inscribed angles like ∠N with the intercepted arc, the equation is ∠N=1/2MP. (Inscribed angles are always half the degree of the arc length.) Plug in the corresponding value to get ∠N=1/2(64) to get 32°. When finding the angle of the intercepted arc with inscribed angles like NQ, the equation is NQ=2(∠P). Plug in the corresponding value to get 2(53) to get 106°.

5 0
3 years ago
Read 2 more answers
Please help asap!!!
sp2606 [1]

Answer:

y=\frac{1}{6} (x+5)^2-4.5

y=\frac{-1}{20} (x-10)^2+1

Step-by-step explanation:

focus at (-5, -3), and directrix y = -6

Directrix y=-6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

(h,k) is the center

P is the distance between focus and vertex

distance between focus and directrix = 2p

distance between -3  and y=-6 is 3

2p = 3

p = 3/2 or p = 1.5

Focus is (h, k+p)

given focus is (-5, -3) so h= -5  and k+p = -3

k+p=-3, plug in 1.5 for p

k + 1.5 = -3

subtract 1.5 on both sides

k = -4.5

(x-h)^2 = 4p(y-k)

(x+5)^2= 4(1.5) (y+4.5)

(x+5)^2= 6(y+4.5)

divide by 6 on both sides

then subtract 4.5 on both sides

y=\frac{1}{6} (x+5)^2-4.5

focus at (10, -4), and directrix y = 6.

Directrix y=6 so its  a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

distance between focus and directrix = 2p

distance between -4  and y=6 is -4-6=-10

2p = -10

p = -5

Focus is (h, k+p)

given focus is (10, -4) so h= 10  and k+p = -4

k+p=-4, plug in 5 for p

k - 5 = -4

add 5 on both sides

k = 1

(x-h)^2 = 4p(y-k)

(x-10)^2= 4(-5) (y-1)

(x-10)^2= -20(y-1)

divide by -20 on both sides and add 1 on both sides

y=\frac{-1}{20} (x-10)^2+1


8 0
3 years ago
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