Answer:
1) 0.1667
2) 0.8333
3) 1
Step-by-step explanation:
Let A be the event that 3 is observed on the first trial.
Let B be the event that at least two trials are required to observe a 3
a) A six-sided die has 6 possible outcomes of 1,2,3,4,5,6
3 is one of the six possible outcomes
P(A) = no of favourable outcomes /no of possible outcomes
P(A) = 1/6 = 0.1667
b) The event of requiring at least two trials to observe a 3 is the event of not observing a 3 on the first trial.
P(B) = P(A')
P(A')= 1 - P(A)
P(B) = 1 - 1/6
= 5/6 = 0.8333
c) P(AnB) = P(A) + P(B)
= 1/6 + 5/6
= 6/6 = 1
10 rows because that's right
Here, you know that 12 people answered.
Therefore :
Take the "M" for mean :
In short, you answer would be C. 3.5.Hope this helps !
Photon
Answer:
5.8
Step-by-step explanation:
To get the mean, add up all the numbers
9+4+8+3+5 = 29
Then divide by how many numbers there are (5)
29/5 =5.8
The mean is 5.8
