Not for sure but maybe, -0.39285714285 if it’s correct hope it helps!
first 1/8 then 4/8 and lastly 7/8
Answer:
Negative numbers can't have a square root so they are all undefine and so is 7.
Step-by-step explanation:
a:
Just divide both sides by 7. Since 7 is positive, you don't need to change the inequality sign:
![7j>77\iff j>11\}](https://tex.z-dn.net/?f=7j%3E77%5Ciff%20j%3E11%5C%7D)
In set notation, we write
![\{j \in \mathbb{R}\ :\ j>11](https://tex.z-dn.net/?f=%5C%7Bj%20%5Cin%20%5Cmathbb%7BR%7D%5C%20%3A%5C%20j%3E11)
b:
Subtract 9 from both sides:
![17\leq x+9 \iff 8\leq x](https://tex.z-dn.net/?f=17%5Cleq%20x%2B9%20%5Ciff%208%5Cleq%20x)
In set notation, we write
![\{x \in \mathbb{R}\ :\ x\geq 8\}](https://tex.z-dn.net/?f=%5C%7Bx%20%5Cin%20%5Cmathbb%7BR%7D%5C%20%3A%5C%20x%5Cgeq%208%5C%7D)