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lesantik [10]
2 years ago
7

X to the power of 2 add 3x

Mathematics
1 answer:
faust18 [17]2 years ago
8 0

Answer:

Hope this helps

Step-by-step explanation:

a) x^2 + 3x = x(x+3)

b) 2x^2 - 8x = 2x(x - 4)

c) 6x + 9x^3 = 3x(2 + 3x^2)

d) 12x^3 - 4x^2 = 4x^2(3x - 1)

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11. Given: TQ bisects ZRTP, QS || PT<br> RT = 30. Find QP, RS and QS
yaroslaw [1]

QP=24 cm

RS=11.25 cm

QS=18.75 cm

<u>Explanation</u>:

Given that TQ bisects <RTP

therefore(1)

consider ΔRQS and ΔRPT

QS||PT,RP and RT are transversals

(alternate angles)(2)

comparing (1) and (2)

and triangle SQT is isocelus

Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)

Therefore <RQS=<RPT(corresponding angles)

<RSQ=<RTP(corresponding angles)

therefore by AA criterion for similarity

ΔRQS~ΔRPT

According to the property of similar triangles

RQ/RP=RS/RT=QS/PT9/RP=X/30=QS/50\\9/RP=X/30=(30-X)/50\\X/30=(30-X)/50\\50X=30(30-X)\\50X=900-30X\\50X+30X=900\\80X=900\\X=900/80=11.25\\RS=11.25 cm\\QS=30-X=30-11.25\\QS=18.75 cm\\9/RP=X/30\\9/RP=11.25/30\\9*30/11.25=RP\\RP=24 cm

3 0
3 years ago
!!20 points and Brainliest please help!!!
vitfil [10]

D) ac + ad + bc + bd

Hope it helps :)

7 0
2 years ago
Read 2 more answers
g In 2013, the Pew Research Foundation reported that 43% of U.S. adults report that they live with one or more chronic condition
SOVA2 [1]

Answer:

We are 95% confident that the true proportion of U.S. adults who live with one or more chronic conditions is between 39.7% and 46.33%

Step-by-step explanation:

From the question we are told that

  The  sample  proportion is \r p = 43\%  = 0.43

   The  standard error is SE =  0.017

Given that the confidence level is 95%  then the level of significance is mathematically represented as  

      \alpha =  (100-95)\%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as

     E = Z_{\frac{\alpha }{2} } *  SE

=>    E = 1.96 *  0.017

=>     E = 0.03332

Generally 95% confidence interval is mathematically represented as

      \r p -E <  p <  \r p +E

=>   0.43 -0.03332 <  p <  0.43 + 0.03332

=>    0.39668 <  p <  0.46332

Converting to percentage

(0.39668 * 100)<  p <  (0.46332*100)        

39.7\% <  p < 46.33 \%    

7 0
3 years ago
Steve opens a bank account. The amount, in dollars, in the account x weeks after the account is opened can be modeled by functio
ANTONII [103]

The missing options are:

A.\ f(20) =5,000

B.\ f(5000) = 20

C. In the xy plane, point (20, 5,000) is on the graph y = f(x).

D. In the xy plane, point (5,000,20) is on the graph y = f(x)

Answer:

A.\ f(20) =5,000

C. In the xy plane, point (20, 5,000) is on the graph y = f(x).

Step-by-step explanation:

Given

Represent amount with y and weeks with x

So, we have:

x = 20 when y = 5000

Required

Select 2 correct options

A point on a graph can be illustrated using  (x,y)

So, when x = 20 and y = 5000 ----- given

(x,y) implies that:

(x,y) = (20,5000)

We got (20,5000) by substituting 20 for x and 5000 for y

<em />

<em>From the list of given options, the above represented of (x,y) is illustrated in option C</em>

Represent (x,y) as a function, we have:

y = f(x)

Substitute values for x and y

5000 = f(20)

Reorder

f(20) = 5000

<em></em>

The above is illustrated in option A

<em>Hence, A and C answers the question</em>

3 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
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