Y = x^3, the cubing function, is an odd function, because the highest power of x is 3 and there are no even powers of x in this formula. The graph is symmetrical with respect to the origin. It begins in Quadrant III and ends in Quadrant I.
Answer:
Yes
Step-by-step explanation:
To determine if (5, 4) is a solution, substitute the x and y values into the left side of the inequalities and compare the result to the right side.
6(5) - 5(4) = 30 - 20 = 10 < 11 ← True
- 3(5) + 2(4) = - 15 + 8 = - 7 < - 8 ← True
Since both inequalities are true then (5, 4) is a solution to the system
Answer:
ITS A
Step-by-step explanation:
your welcome honey :)
Answer:
Step-by-step explanation:
we can do like
8y-7x+2y² -x-5
= 2y^2 + 8y - 8x - 5 ( we know that - 5 = 8 - 13)
= 2( y^2 + 4y + 4) - 8x - 13
= 2 (y+2)^2 -8x - 13
I do not know that you wrongly type but here is the answer.