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Vilka [71]
3 years ago
15

Solve for the value of m. 38° (8m+4)°

Mathematics
1 answer:
Neporo4naja [7]3 years ago
4 0

Answer:

m = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Equality Properties
  • Combining Like Terms

<u>Geometry</u>

  • Complementary Angles - Angles that add up to 90°

Step-by-step explanation:

<u>Step 1: Set Up Equation</u>

<em>The 2 angles must add up to 90°.</em>

(8m + 4)° + 38° = 90°

<u>Step 2: Solve for </u><em><u>m</u></em>

  1. Combine like terms:                    8m + 42 = 90
  2. Isolate <em>m</em> term:                             8m = 48
  3. Isolate <em>m</em>:                                      m = 6
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recalling that d = rt, distance = rate * time.


we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?


\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

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\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


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3 years ago
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