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OLEGan [10]
3 years ago
11

Elliot has been running a lawn care business since 2000. He cuts grass, trims, and weed whacks yards for his customers throughou

t the season. Each year, he has increased his fee by the same amount. The table shows what Elliot charged each customer for two given years of his business:
Year Lawn Care Fee

2000 $750

2010 $1350



A. What is the rate of change and initial value for Elliot’s business? How do you know?

B. Write an equation in slope-intercept form to represent the fees that Elliot charges each year.
Mathematics
1 answer:
Elena L [17]3 years ago
7 0

Answer:

A: initial value: $750; rare of change: $60

B: y = 60t + 750

Step-by-step explanation:

Initial value = value when he started ( in 2000) =$ 750

Each year he add a constants to that value

'y' will be the amount he get after t years a amount increase each year

y = 750 + at

In 2010 his free = 1350

t = 2010 - 2000 = 10 year

y = 1350

y = 750 + at

1350 = 750 + 10 a

600 = 10a

a = 60

y = 750 + 60t ( his fee as a function of time)

In slope form: y = 60t + 750

He increases he fee by $60 a year.

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ANSWER

\boxed {( \frac{1}{2} , 1)}

EXPLANATION

The given parallelogram has vertices,

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The diagonals of the parallelogram bisect each other.

From the diagram, we can see that, the diagonals have coordinates L(0,-3),N(1,5)

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The midpoint of any of the diagonals will give us the coordinates of intersection of the diagonals.

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Or we could have also used,M(-2,1),O(3,1) to get,

(\frac{-2+3}{2}, \frac{ 1+1}{2})

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