Answer: 0.052
Step-by-step explanation:
Given : The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and a standard deviation of 9.2 gigagrams per year.
i.e.
and 
Let x denotes the yearly amounts of carbon emissions from cars in Belgium.
Then, the probability that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 12.8 gigagrams and 14.0 gigagrams per year will be :-

Hence, the required probability = 0.052
Answer:

Step-by-step explanation:
<h2> (-1 3/5) / (-2/3) =

</h2><h2>

=

</h2>
Answer:
2x-5y-20=0
Step-by-step explanation:
2y=-8+4/5x
2y+8-4/5x=0
10y+40-4x=0
5y+20-2x=0
-2x+5y+20=0
2x-5y-20=0
So we are given two points, say P1(4,7), P2(x,19).
Slope is given by
m=3=(y2-y1)/(x2-x1)=(19-7)/(x-4)
solve for x
3=(19-7)/(x-4)
cross multiply
3(x-4)=12
3x-12=12
3x=12+12=24
x=8