Answer:
$9$
Step-by-step explanation:
Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.
To find: number that Thea originally entered
Solution:
The final number is $243$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $243$ must be $324$.
As previously the number was squared, so the number before $324$ must be $18$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $18$ must be $81$
As previously the number was squared, so the number before $81$ must be $9$.
False because doing the math doesn’t match
Part A: 5 is the coefficient, w is the variable, 50 is the constant
Part B: 10 x 5 = 50 + 2 x 20 = 40+ 50 = $140
Part C: the constant,50,would change and become 85. Hope this helps :)
Answer:
<h2>i need to see all the answers but yeah </h2>
Step-by-step explanation:
4*6 = 24. (4 dollars to spare)
(5*2) + (4*4) = 26 (2 dollars to spare)
^ ^
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